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Nilai dari cos1680−cos1020sin780−sin120​=...

Pertanyaan

Nilai dari fraction numerator sin space 78 to the power of 0 minus sin 12 to the power of 0 over denominator cos space 168 to the power of 0 minus cos 102 to the power of 0 end fraction equals...

  1. -1

  2. negative 1 half square root of 2

  3. 0

  4. 1 half square root of 2

  5. 1

Pembahasan:

R u m u s space p e n g u r a n g a n space sin u s space d a n space cos i n u s  sin invisible function application alpha minus sin invisible function application beta equals 2 space cos invisible function application fraction numerator alpha plus beta over denominator 2 end fraction space space sin invisible function application fraction numerator alpha minus beta over denominator 2 end fraction  cos invisible function application alpha minus cos invisible function application beta equals negative 2 space sin invisible function application fraction numerator alpha plus beta over denominator 2 end fraction space space sin invisible function application fraction numerator alpha minus beta over denominator 2 end fraction  fraction numerator s i n invisible function application 78 to the power of o minus s i n invisible function application 12 to the power of o over denominator c o s invisible function application 68 to the power of o minus c o s invisible function application 102 to the power of o end fraction equals fraction numerator 2 space cos invisible function application begin display style fraction numerator 78 plus 12 over denominator 2 end fraction end style space space sin invisible function application left parenthesis begin display style fraction numerator 78 minus 12 over denominator 2 end fraction end style right parenthesis over denominator negative 2 space sin invisible function application begin display style fraction numerator 168 plus 102 over denominator 2 end fraction end style space space sin invisible function application begin display style fraction numerator 168 minus 102 over denominator 2 end fraction end style end fraction  equals fraction numerator 2 cos invisible function application 45 to the power of o sin invisible function application 33 to the power of o over denominator negative 2 sin invisible function application 135 to the power of o sin invisible function application 33 to the power of o end fraction  equals fraction numerator cos invisible function application 45 to the power of o over denominator negative s i n invisible function application left parenthesis 180 minus 45 right parenthesis to the power of o end fraction  equals fraction numerator cos invisible function application 45 to the power of o over denominator negative s i n invisible function application 45 to the power of o end fraction  equals negative fraction numerator 1 over denominator t a n invisible function application 45 to the power of o end fraction equals negative 1

Jawaban terverifikasi

Dijawab oleh:

F. Kurnia

Mahasiswa/Alumni Universitas Jember

Terakhir diupdate 04 Oktober 2021

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