Roboguru

Nilai dari

Pertanyaan

Nilai dari limit as straight x rightwards arrow infinity of space fraction numerator open parentheses 4 straight x minus 3 close parentheses cubed over denominator open parentheses 2 straight x minus 1 close parentheses open parentheses straight x squared plus 2 straight x plus 3 close parentheses end fraction equals..... 

  1. 64 

  2. 32 

  3. 24 

  4. 16 

  5. 8 

Pembahasan Soal:

Nilai limit yang diberikan dapat ditentukan dengan cara:

limit as straight x rightwards arrow infinity of space fraction numerator open parentheses 4 straight x minus 3 close parentheses cubed over denominator open parentheses 2 straight x minus 1 close parentheses open parentheses straight x squared plus 2 straight x plus 3 close parentheses end fraction equals limit as straight x rightwards arrow infinity of space fraction numerator 64 straight x cubed minus 144 straight x squared plus 108 straight x minus 27 over denominator 2 straight x cubed plus 3 straight x squared plus 4 straight x minus 3 end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals limit as straight x rightwards arrow infinity of space fraction numerator begin display style fraction numerator 64 straight x cubed minus 144 straight x squared plus 108 straight x minus 27 over denominator straight x cubed end fraction end style over denominator begin display style fraction numerator 2 straight x cubed plus 3 straight x squared plus 4 straight x minus 3 over denominator straight x cubed end fraction end style end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals fraction numerator 64 minus 0 plus 0 minus 0 over denominator 2 plus 0 plus 0 minus 0 end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 64 over 2 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 32 

Jadi, jawaban yang benar adalah B.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 10 Juni 2021

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