Pertanyaan

Nilai dari x → 1 lim ​ 2 − 3 x + 1 ​ 3 x + 6 ​ − 3 ​ = ....

Nilai dari  

  1. 1 

  2. 1 half 

  3. fraction numerator negative 1 over denominator 3 end fraction 

  4. 3 over 2 

  5. fraction numerator negative 2 over denominator 3 end fraction 

F. Nur

Master Teacher

Mahasiswa/Alumni Universitas Muhammadiyah Malang

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah E.

jawaban yang tepat adalah E.

Pembahasan

Dengan mengalikan akar sekawan. Jadi, jawaban yang tepat adalah E.

Dengan mengalikan akar sekawan.

begin mathsize 12px style table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell limit as x rightwards arrow 1 of fraction numerator square root of 3 x plus 6 end root minus 3 over denominator 2 minus square root of 3 x plus 1 end root end fraction end cell row blank equals cell limit as x rightwards arrow 1 of fraction numerator square root of 3 x plus 6 end root minus 3 over denominator 2 minus square root of 3 x plus 1 end root end fraction times fraction numerator 2 plus square root of 3 x plus 1 end root over denominator 2 plus square root of 3 x plus 1 end root end fraction times fraction numerator square root of 3 x plus 6 end root plus 3 over denominator square root of 3 x plus 6 end root plus 3 end fraction space end cell row blank equals cell limit as x rightwards arrow 1 of fraction numerator open parentheses square root of 3 x plus 6 end root close parentheses squared minus 3 squared over denominator 2 squared minus open parentheses square root of 3 x plus 1 end root close parentheses squared end fraction times fraction numerator 2 plus square root of 3 x plus 1 end root over denominator square root of 3 x plus 6 end root plus 3 end fraction end cell row space equals cell limit as x rightwards arrow 1 of fraction numerator 3 x plus 6 minus 9 over denominator 4 minus open parentheses 3 x plus 1 close parentheses end fraction times fraction numerator 2 plus square root of 3 x plus 1 end root over denominator square root of 3 x plus 6 end root plus 3 end fraction space end cell row blank equals cell limit as x rightwards arrow 1 of fraction numerator 3 x minus 3 over denominator 3 minus 3 x end fraction times fraction numerator 2 plus square root of 3 x plus 1 end root over denominator square root of 3 x plus 6 end root plus 3 end fraction space end cell row blank equals cell limit as x rightwards arrow 1 of fraction numerator negative up diagonal strike open parentheses 3 minus 3 x close parentheses end strike over denominator up diagonal strike open parentheses 3 minus 3 x close parentheses end strike end fraction times fraction numerator 2 plus square root of 3 x plus 1 end root over denominator square root of 3 x plus 6 end root plus 3 end fraction space end cell row blank equals cell limit as x rightwards arrow 1 of minus fraction numerator 2 plus square root of 3 x plus 1 end root over denominator square root of 3 x plus 6 end root plus 3 end fraction end cell row space equals cell negative fraction numerator 2 plus square root of 3 times 1 plus 1 end root over denominator square root of 3 times 1 plus 6 end root plus 3 end fraction end cell row space equals cell negative fraction numerator 2 plus square root of 4 over denominator square root of 9 plus 3 end fraction end cell row space equals cell negative fraction numerator 2 plus 2 over denominator 3 plus 3 end fraction space end cell row blank equals cell negative 4 over 6 space end cell row blank equals cell negative 2 over 3 end cell row blank equals cell fraction numerator negative 2 over denominator 3 end fraction end cell end table end style    

Jadi, jawaban yang tepat adalah E.

39

0.0 (0 rating)

Iklan

Pertanyaan serupa

Nilai x → p lim ​ x ​ − p ​ x x ​ − p p ​ ​ = ...

52

5.0

Jawaban terverifikasi

Iklan

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Fitur Roboguru

Topik Roboguru

Hubungi Kami

Ruangguru WhatsApp

081578200000

Email info@ruangguru.com

info@ruangguru.com

Contact 02140008000

02140008000

Ikuti Kami

©2022 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia