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Nilai dari ∫−12​(x−1)(3x+5)dx  adalah...

Pertanyaan

Nilai dari 12(x1)(3x+5)dx  adalah...

  1. begin mathsize 14px style negative 7 end style 

  2. begin mathsize 14px style negative 3 end style 

  3. begin mathsize 14px style negative 1 end style 

  4. begin mathsize 14px style 3 end style 

  5. begin mathsize 14px style 7 end style 

Pembahasan Soal:

12(x1)(3x+5)dx======12(3x2+2x5)dx[33x3+22x25x]12[x3+x25x]12(23+225(2))((1)3+(1)25(1))253 

Jadi, jawaban yang tepat adalah B.

Pembahasan terverifikasi oleh Roboguru

Dijawab oleh:

R. Bella

Mahasiswa/Alumni UIN Syarif Hidayatullah Jakarta

Terakhir diupdate 13 September 2021

Roboguru sudah bisa jawab 91.4% pertanyaan dengan benar

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Pertanyaan yang serupa

Nilai  yang memenuhi   adalah...

Pembahasan Soal:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell integral subscript negative 1 end subscript superscript 3 left parenthesis 4 x plus p right parenthesis dx end cell equals 8 row cell open square brackets fraction numerator 4 x squared over denominator 2 end fraction plus p x close square brackets subscript negative 1 end subscript superscript 3 end cell equals 8 row cell open square brackets 2 x squared plus p x close square brackets subscript negative 1 end subscript superscript 3 end cell equals 8 row cell open parentheses 2 left parenthesis 3 squared right parenthesis plus p left parenthesis 3 right parenthesis close parentheses minus open parentheses 2 left parenthesis negative 1 right parenthesis squared plus p left parenthesis negative 1 right parenthesis close parentheses end cell equals 8 row cell open parentheses 18 plus 3 p close parentheses minus open parentheses 2 minus p close parentheses end cell equals 8 row cell 18 plus 3 p minus 2 plus p end cell equals 8 row cell 16 plus 4 p end cell equals 8 row cell 4 p end cell equals cell negative 8 end cell row p equals cell negative 2 end cell end table end style 

Jadi, jawaban yang tepat adalah D

3

Roboguru

Nilai dari  adalah ...

Pembahasan Soal:

  begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell integral subscript 2 superscript 6 3 space dx end cell equals cell left square bracket 3 x right square bracket subscript 2 superscript 6 space end cell row blank equals cell 3 left parenthesis 6 right parenthesis minus 3 left parenthesis 2 right parenthesis end cell row blank equals cell 18 minus 6 end cell row blank equals 12 end table end style

Jadi, jawaban yang tepat adalah D

1

Roboguru

Nilai dari  adalah ...

Pembahasan Soal:

table attributes columnalign right center left columnspacing 0px end attributes row cell integral subscript negative 1 end subscript superscript 4 size 14px left parenthesis size 14px 2 size 14px x size 14px plus size 14px 3 size 14px right parenthesis size 14px dx end cell size 14px equals cell begin mathsize 14px style left square bracket fraction numerator 2 x squared over denominator 2 end fraction plus 3 x right square bracket end style subscript size 14px minus size 14px 1 end subscript superscript size 14px 4 end cell row blank size 14px equals cell begin mathsize 14px style left square bracket x squared plus 3 x right square bracket end style subscript size 14px minus size 14px 1 end subscript superscript size 14px 4 end cell row blank size 14px equals cell begin mathsize 14px style left parenthesis 4 squared plus 3 left parenthesis 4 right parenthesis right parenthesis end style size 14px minus begin mathsize 14px style left parenthesis left parenthesis negative 1 right parenthesis squared plus 3 left parenthesis negative 1 right parenthesis right parenthesis end style end cell row blank size 14px equals cell size 14px 28 size 14px minus size 14px left parenthesis size 14px minus size 14px 2 size 14px right parenthesis end cell row blank size 14px equals size 14px 30 end table

Jadi, jawaban yang tepat adalah C

1

Roboguru

Hasil dari    adalah...

Pembahasan Soal:

table attributes columnalign right center left columnspacing 0px end attributes row cell integral subscript negative 2 end subscript superscript 4 size 14px left parenthesis size 14px 6 size 14px x to the power of size 14px 2 size 14px plus size 14px 3 size 14px x size 14px minus size 14px 1 size 14px right parenthesis size 14px dx end cell size 14px equals cell begin mathsize 14px style left square bracket fraction numerator 6 x cubed over denominator 3 end fraction plus begin inline style fraction numerator 3 x squared over denominator 2 end fraction end style minus x right square bracket end style subscript size 14px minus size 14px 2 end subscript superscript size 14px 4 end cell row blank size 14px equals cell begin mathsize 14px style open square brackets 2 x cubed begin inline style plus end style begin inline style fraction numerator 3 x squared over denominator 2 end fraction end style begin inline style minus end style begin inline style x end style close square brackets subscript negative 2 end subscript superscript 4 end style end cell row blank size 14px equals cell begin mathsize 14px style open parentheses 2 left parenthesis 4 cubed right parenthesis plus fraction numerator 3 left parenthesis 4 right parenthesis squared over denominator 2 end fraction begin inline style minus end style begin inline style 4 end style close parentheses end style size 14px minus begin mathsize 14px style open parentheses 2 left parenthesis negative 2 right parenthesis cubed plus fraction numerator 3 left parenthesis negative 2 right parenthesis squared over denominator 2 end fraction begin inline style minus end style begin inline style 4 end style close parentheses end style end cell row blank size 14px equals cell size 14px 148 size 14px minus size 14px left parenthesis size 14px minus size 14px 14 size 14px right parenthesis end cell row blank size 14px equals size 14px 162 end table 

1

Roboguru

Nilai dari   adalah...

Pembahasan Soal:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell integral subscript 1 superscript 3 left parenthesis 3 x squared plus 2 x minus 1 right parenthesis d x end cell equals cell open square brackets fraction numerator 3 x cubed over denominator 3 end fraction plus fraction numerator 2 x squared over denominator 2 end fraction minus x close square brackets subscript 1 superscript 3 end cell row blank equals cell open square brackets x cubed plus x squared minus x close square brackets subscript negative 1 end subscript superscript 3 end cell row blank equals cell open parentheses 3 cubed plus 3 squared minus 3 close parentheses minus open parentheses left parenthesis negative 1 right parenthesis cubed plus left parenthesis negative 1 right parenthesis squared minus left parenthesis negative 1 right parenthesis close parentheses end cell row blank equals cell 33 minus 1 end cell row blank equals 32 row blank blank blank end table end style

Jadi, jawaban yang tepat adalah A 

1

Roboguru

Roboguru sudah bisa jawab 91.4% pertanyaan dengan benar

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