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Pertanyaan

Nilai dari adalah ....

Nilai dari begin mathsize 14px style integral subscript 1 superscript 4 space open parentheses 3 square root of x minus fraction numerator 1 over denominator square root of x end fraction close parentheses d x end style adalah ....

  1. 20

  2. 12

  3. 8

  4. 4

  5. 2

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S. Intan

Master Teacher

Mahasiswa/Alumni Institut Pertanian Bogor

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Pembahasan

begin mathsize 14px style integral subscript 1 superscript 4 open parentheses 3 square root of straight x minus fraction numerator 1 over denominator square root of straight x end fraction close parentheses dx  equals integral subscript 1 superscript 4 open parentheses 3 straight x to the power of 1 half end exponent minus straight x to the power of negative 1 half end exponent close parentheses dx  equals open square brackets 3.2 over 3 straight x to the power of 3 over 2 end exponent minus 2 straight x to the power of 1 half end exponent close square brackets subscript 1 superscript 4  equals open square brackets 2 x to the power of 2 over 3 end exponent minus 2 x to the power of 1 half end exponent close square brackets subscript blank superscript blank  equals open parentheses 2 open parentheses 4 close parentheses to the power of 3 over 2 end exponent minus 2 open parentheses 4 close parentheses to the power of 1 half end exponent close parentheses minus open parentheses 2 open parentheses 1 close parentheses to the power of 3 over 2 end exponent minus 2 open parentheses 1 close parentheses to the power of 1 half end exponent close parentheses  equals left parenthesis 16 minus 4 right parenthesis minus left parenthesis 2 minus 2 right parenthesis  equals 12 space end style

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3

Chiara Dewi Chatlina

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Nilai dari ∫ 1 3 ​ ( 6 x 2 − 2 x + 7 ) d x = ....

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