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Nilai dari  adalah ...

Pertanyaan

 Nilai dari Error converting from MathML to accessible text. adalah ...

  1. 62

  2. 32

  3. 1 over 32

  4. 0

Pembahasan Video:

Pembahasan Soal:

table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses 2 squared close parentheses cubed minus 8 squared space colon space open parentheses 1 half close parentheses to the power of negative 5 end exponent end cell equals cell 2 to the power of 2 cross times 3 end exponent minus 8 squared space colon space open parentheses 2 to the power of negative 1 end exponent close parentheses to the power of negative 5 end exponent end cell row blank equals cell 2 to the power of 6 minus 8 squared space colon space 2 to the power of 5 end cell row blank equals cell 64 minus open parentheses 64 space colon space 32 close parentheses end cell row blank equals cell 64 minus 2 end cell row blank equals 62 end table

Jadi, jawaban yang tepat adalah A

Pembahasan terverifikasi oleh Roboguru

Dijawab oleh:

N. Puspita

Terakhir diupdate 13 September 2021

Roboguru sudah bisa jawab 91.4% pertanyaan dengan benar

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Pertanyaan yang serupa

Jika  dan , nilai  adalah ....

Pembahasan Soal:

Sifat bilangan berpangkatan yang digunakan:
open parentheses a to the power of m close parentheses to the power of n equals a to the power of m n end exponent 

Dengan menerapkan sifat pemangkatan bilangan berpangkat, diperoleh:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell 5 to the power of 10 x end exponent end cell equals 1600 row cell 5 to the power of 2 times 5 x end exponent end cell equals 1600 row cell open parentheses 5 to the power of 5 x end exponent close parentheses squared end cell equals 1600 row cell square root of open parentheses 5 to the power of 5 x end exponent close parentheses squared end root end cell equals cell square root of 1600 end cell row cell 5 to the power of 5 x end exponent end cell equals 40 end table end style 

Selanjutnya, dengan menerapkan sifat-sifat bilangan berpangkat, diperoleh perhitungan sebagai berikut.

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses 5 to the power of x minus 1 end exponent close parentheses to the power of 5 over 8 to the power of open parentheses negative square root of y close parentheses end exponent end cell equals cell 5 to the power of 5 open parentheses x minus 1 close parentheses end exponent over open parentheses 2 cubed close parentheses to the power of negative square root of y end exponent end cell row blank equals cell 5 to the power of 5 x minus 5 end exponent over 2 to the power of negative 3 square root of y end exponent end cell row blank equals cell fraction numerator begin display style 5 to the power of 5 x end exponent over 5 to the power of 5 end style over denominator begin display style 1 over 2 to the power of 3 square root of y end exponent end style end fraction end cell row blank equals cell 5 to the power of 5 x end exponent over 5 to the power of 5 cross times 2 to the power of 3 square root of y end exponent end cell row blank equals cell 5 to the power of 5 x end exponent over 5 to the power of 5 cross times open parentheses 2 to the power of square root of y end exponent close parentheses cubed end cell row blank equals cell 40 over 5 to the power of 5 cross times 25 cubed end cell row blank equals cell 40 over 5 to the power of 5 cross times open parentheses 5 squared close parentheses cubed end cell row blank equals cell 40 over 5 to the power of 5 cross times 5 to the power of 2 times 3 end exponent end cell row blank equals cell 40 over 5 to the power of 5 cross times 5 to the power of 6 end cell row blank equals cell 40 cross times 5 to the power of 6 minus 5 end exponent end cell row blank equals cell 40 cross times 5 to the power of 1 end cell row blank equals cell 40 cross times 5 end cell row blank equals 200 end table end style 

Jadi, nilai begin mathsize 14px style open parentheses 5 to the power of x minus 1 end exponent close parentheses to the power of 5 over 8 to the power of open parentheses negative square root of y close parentheses end exponent end style adalah 200.

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Roboguru

Hasil dari ....

Pembahasan Soal:

a to the power of m space cross times space a to the power of n space equals space a to the power of m plus n end exponent  2 to the power of negative 3 end exponent cross times 2 to the power of negative 2 end exponent space equals space 2 to the power of negative 3 minus 2 end exponent space equals space 2 to the power of negative 5 end exponent space equals space 1 over 32

Jawaban D

 

0

Roboguru

Jika  dan , nilai dari  adalah ....

Pembahasan Soal:

Ingat!

Sifat perpangkatan antara lain:

  1. open parentheses a cross times b close parentheses to the power of m equals a to the power of m cross times b to the power of m 
  2. a to the power of m cross times a to the power of n equals a to the power of m plus n end exponent 
  3. a to the power of m space colon space a to the power of n equals a to the power of m minus n end exponent 
  4. a to the power of negative m end exponent equals 1 over a to the power of m space d e n g a n space a to the power of m not equal to 0 

Untuk begin mathsize 14px style a equals 4 end style dan begin mathsize 14px style b equals 5 end style, diperoleh

table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator 4 to the power of 5 open parentheses 4 to the power of negative 2 end exponent times 5 close parentheses over denominator open parentheses 4 times 5 close parentheses squared end fraction end cell equals cell fraction numerator 4 to the power of 5 times 4 to the power of negative 2 end exponent times 5 over denominator 4 squared times 5 squared end fraction space bold left parenthesis bold sifat bold space bold 1 bold right parenthesis end cell row blank equals cell fraction numerator 4 to the power of 5 plus left parenthesis negative 2 right parenthesis end exponent times 5 over denominator 4 squared times 5 squared end fraction space bold left parenthesis bold sifat bold space bold 2 bold right parenthesis end cell row blank equals cell fraction numerator 4 cubed times 5 over denominator 4 squared times 5 squared end fraction end cell row blank equals cell 4 to the power of 3 minus 2 end exponent times 5 to the power of 1 minus 2 end exponent space bold left parenthesis bold sifat bold space bold 3 bold right parenthesis end cell row blank equals cell 4 times 5 to the power of negative 1 end exponent end cell row blank equals cell 4 times 1 fifth space bold left parenthesis bold sifat bold space bold 4 bold right parenthesis end cell row blank equals cell 4 over 5 end cell end table 

Jadi, begin mathsize 14px style fraction numerator a to the power of 5 open parentheses a to the power of negative 2 end exponent b close parentheses over denominator open parentheses a b close parentheses squared end fraction end styleequals table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell 4 over 5 end cell end table.

0

Roboguru

Pembahasan Soal:

Gunakan space sifat minus sifat space perpangkatan space berikut space colon  left parenthesis a to the power of p right parenthesis to the power of q equals a to the power of p q end exponent  a to the power of p over a to the power of q equals a to the power of p minus q end exponent  a to the power of negative p end exponent equals 1 over a to the power of p    S e d e r h a n a k a n space b e n t u k space p a n g k a t space h i n g g a space y a n g space p a l i n g space s e d e r h a n a space  fraction numerator 27 to the power of negative 1 end exponent a cubed b to the power of 6 over denominator 3 to the power of negative 3 end exponent a cubed b to the power of negative 6 end exponent end fraction equals fraction numerator left parenthesis 3 cubed right parenthesis to the power of negative 1 end exponent a cubed b to the power of 6 over denominator 3 to the power of negative 3 end exponent a cubed b to the power of negative 6 end exponent end fraction equals fraction numerator horizontal strike 3 to the power of negative 3 end exponent a cubed end strike b to the power of 6 over denominator horizontal strike 3 to the power of negative 3 end exponent a cubed end strike b to the power of negative 6 end exponent end fraction equals b to the power of 12

0

Roboguru

Sederhanakanlah persamaan berikut !

Pembahasan Soal:

table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator straight a cubed times straight b to the power of negative 2 end exponent over denominator straight a squared times straight b to the power of negative 5 end exponent times straight c to the power of negative 3 end exponent end fraction end cell equals cell straight a to the power of 3 minus 2 end exponent times straight b to the power of negative 2 plus 5 end exponent times straight c cubed end cell row blank equals cell straight a times straight b cubed times straight c cubed end cell end table


Jadi bentuk sederhana dari fraction numerator straight a cubed times straight b to the power of negative 2 end exponent over denominator straight a squared times straight b to the power of negative 5 end exponent times straight c to the power of negative 3 end exponent end fraction adalah table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell straight a times straight b cubed times straight c cubed end cell end table.

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