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Tentukan x → 2 lim ​ 36 x 2 − 3 x − 4 x 2 + 5 x ​ !

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A. Salim

Master Teacher

Mahasiswa/Alumni Universitas Pelita Harapan

Jawaban terverifikasi

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nilai adalah .

nilai begin mathsize 14px style limit as x rightwards arrow 2 of fraction numerator x squared plus 5 x over denominator 36 x squared minus 3 x minus 4 end fraction end style adalah begin mathsize 14px style 7 over 67 end style.

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Pembahasan

disubtitusikan pada limit tersebut Jadi, nilai adalah .

begin mathsize 14px style x equals 2 end style disubtitusikan pada limit tersebut

begin mathsize 14px style limit as x rightwards arrow 2 of fraction numerator x squared plus 5 x over denominator 36 x squared minus 3 x minus 4 end fraction equals fraction numerator 2 squared plus 5 open parentheses 2 close parentheses over denominator 36 open parentheses 2 close parentheses squared minus 3 open parentheses 2 close parentheses minus 4 end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals fraction numerator 4 plus 10 over denominator 144 minus 6 minus 4 end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 14 over 134 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 7 over 67 end style 

Jadi, nilai begin mathsize 14px style limit as x rightwards arrow 2 of fraction numerator x squared plus 5 x over denominator 36 x squared minus 3 x minus 4 end fraction end style adalah begin mathsize 14px style 7 over 67 end style.

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