Roboguru

Nilai  adalah ...

Nilai begin mathsize 14px style limit as x rightwards arrow negative 2 of fraction numerator x cubed plus 8 over denominator x plus 2 end fraction end style adalah ...

Jawaban:

Bila kita gunakan cara substitusi maka kita akan mendapatkan bentuk limit tak tentu, jadi kita gunakan cara pemfaktoran

begin mathsize 14px style limit as x rightwards arrow negative 2 of fraction numerator x cubed plus 8 over denominator x plus 2 end fraction equals limit as x rightwards arrow negative 2 of fraction numerator open parentheses x plus 2 close parentheses open parentheses x squared minus 2 x plus 4 close parentheses over denominator x plus 2 end fraction space space space space space space space space space space space space space space space space space space space space equals limit as x rightwards arrow negative 2 of open parentheses x squared minus 2 x plus 4 close parentheses space space space space space space space space space space space space space space space space space space space space equals open parentheses negative 2 close parentheses squared minus 2 open parentheses negative 2 close parentheses plus 4 space space space space space space space space space space space space space space space space space space space space equals 4 plus 4 plus 4 space space space space space space space space space space space space space space space space space space space space equals 12 end style 

Jadi, nilai limitnya adalah 12. 

0

Ruangguru

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ikuti Kami

©2021 Ruangguru. All Rights Reserved