Roboguru

Nilai  = ....

Pertanyaan

Nilai begin mathsize 14px style limit with x rightwards arrow 3 below fraction numerator 2 minus square root of x plus 1 end root over denominator x minus 3 end fraction end style = .... 

Pembahasan Soal:

Gunakan perkalian sekawan.

begin mathsize 14px style limit with x rightwards arrow 3 below fraction numerator 2 minus square root of x plus 1 end root over denominator x minus 3 end fraction end style = begin mathsize 14px style limit with x rightwards arrow 3 below fraction numerator 2 minus square root of x plus 1 end root over denominator x minus 3 end fraction cross times fraction numerator 2 plus square root of x plus 1 end root over denominator 2 plus square root of x plus 1 end root end fraction end style  

begin mathsize 14px style limit with x rightwards arrow 3 below fraction numerator 4 minus left parenthesis x plus 1 right parenthesis over denominator left parenthesis x minus 3 right parenthesis left parenthesis 2 plus square root of x plus 1 end root right parenthesis space end fraction end style 

begin mathsize 14px style limit with x rightwards arrow 3 below fraction numerator negative open parentheses x minus 3 close parentheses over denominator left parenthesis x minus 3 right parenthesis left parenthesis 2 plus square root of x plus 1 end root right parenthesis space end fraction end style 

begin mathsize 14px style fraction numerator negative 1 over denominator 2 plus square root of 4 end fraction equals fraction numerator negative 1 over denominator 4 end fraction end style.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 13 Maret 2021

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