Roboguru

Matriks  dan . Nilai  adalah...

Pertanyaan

Matriks A equals open parentheses table row 1 cell negative 1 end cell row 0 2 end table close parentheses dan B equals open parentheses table row 0 1 row 2 3 end table close parentheses. Nilai left parenthesis B A right parenthesis to the power of negative 1 end exponent adalah...

  1. open parentheses table row cell negative 1 end cell cell 1 half end cell row cell 1 half end cell 1 end table close parentheses 

  2. open parentheses table row cell negative 1 end cell cell 1 half end cell row cell 1 half end cell cell negative 1 end cell end table close parentheses 

  3. open parentheses table row cell negative 1 end cell cell 1 half end cell row cell 1 half end cell 0 end table close parentheses 

  4. open parentheses table row cell negative 1 end cell cell 1 half end cell row cell negative 1 half end cell 0 end table close parentheses 

  5. open parentheses table row cell negative 1 end cell cell negative 1 half end cell row cell 1 half end cell 0 end table close parentheses  

Pembahasan Soal:

Menentukan matriks BA

table attributes columnalign right center left columnspacing 0px end attributes row cell B A end cell equals cell open parentheses table row 0 1 row 2 3 end table close parentheses open parentheses table row 1 cell negative 1 end cell row 0 2 end table close parentheses end cell row blank equals cell open parentheses table row cell 0 times 1 plus 1 times 0 end cell cell 0 times left parenthesis negative 1 right parenthesis plus 1 times 2 end cell row cell 2 times 1 plus 3 times 0 end cell cell 2 times left parenthesis negative 1 right parenthesis plus 3 times 2 end cell end table close parentheses end cell row blank equals cell open parentheses table row 0 2 row 2 4 end table close parentheses end cell end table 

Menentukan determinan matriks BA 

equals 0 times 4 minus 2 times 2 equals 0 minus 4 equals negative 4 

Menentukan matriks left parenthesis B A right parenthesis to the power of negative 1 end exponent

table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell left parenthesis B A right parenthesis to the power of negative 1 end exponent end cell row blank equals cell open parentheses table row 0 2 row 2 4 end table close parentheses to the power of negative 1 end exponent end cell row blank equals cell fraction numerator 1 over denominator negative 4 end fraction open parentheses table row 4 cell negative 2 end cell row cell negative 2 end cell 0 end table close parentheses end cell row blank equals cell open parentheses table row cell negative 1 end cell cell 1 half end cell row cell 1 half end cell 0 end table close parentheses end cell end table 

Jadi, jawaban yang benar adalah C.

 

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 04 Mei 2021

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