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Massa 0,25 mol kalsium karbonat  (25 gr) (Ar C= 12...

Massa 0,25 mol kalsium karbonat Ca C O subscript 3 (25 gr) (Ar C= 12, 0=16, Ca = 40).

Jawaban:

Langkah 1: Menghitung Mr Ca C O subscript bold 3

table attributes columnalign right center left columnspacing 0px end attributes row cell Mr subscript Ca C O subscript 3 end subscript end cell equals cell Ar space Ca and Ar space C plus left parenthesis 3 cross times Ar space O right parenthesis end cell row blank equals cell 40 plus 12 plus left parenthesis 3 cross times 16 right parenthesis end cell row blank equals cell 40 plus 12 plus 48 end cell row blank equals cell 100 space begin inline style bevelled gram over mol end style end cell end table


Langkah 2: Menghitung massa Ca C O subscript bold 3 

table attributes columnalign right center left columnspacing 0px end attributes row cell n subscript Ca C O subscript 3 end subscript end cell equals cell m subscript Ca C O subscript 3 end subscript over Mr subscript Ca C O subscript 3 end subscript end cell row cell 0 comma 25 space mol end cell equals cell fraction numerator m subscript Ca C O subscript 3 end subscript over denominator 100 space bevelled gram over mol end fraction end cell row cell m subscript Ca C O subscript 3 end subscript end cell equals cell 0 comma 25 space mol cross times 100 space begin inline style bevelled gram over mol end style end cell row blank equals cell 25 space gram end cell end table 


Dengan demikian, massa 0,25 mol kalsium karbonat Ca C O subscript bold 3 (Ar C= 12, 0=16, Ca = 40) adalah 25 gram.

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