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Logam magnesium  direaksikan dengan larutan asam k...

Logam magnesium space left parenthesis A subscript r equals 24 space g space mol to the power of negative sign 1 end exponent right parenthesis direaksikan dengan larutan asam klorida sesuai persamaan berikut.
 

Mg open parentheses italic s close parentheses and H Cl left parenthesis italic a italic q right parenthesis yields Mg Cl subscript 2 left parenthesis italic a italic q right parenthesis plus H subscript 2 open parentheses italic g close parentheses
 

Jika massa magnesium yang dilarutkan 9,6 g, jumlah molekul gas H subscript 2 yang terbentuk sebanyak.... left parenthesis A subscript r space colon space Mg equals 12 space g space mol to the power of negative sign 1 end exponent comma space H equals 1 space g space mol to the power of negative sign 1 end exponent comma space dan space Cl equals 35 comma 5 space g space mol to the power of negative sign 1 end exponent right parenthesis

  1. 1 comma 204 cross times 10 to the power of 22 

  2. 2 comma 408 cross times 10 to the power of 22 

  3. 1 comma 204 cross times 10 to the power of 23 

  4. 2 comma 408 cross times 10 to the power of 23 

  5. 3 comma 612 cross times 10 to the power of 23 

Jawaban:

Perbandingan mol zat-zat yang terlibat dalam reaksi sama dengan perbandingan koefisien reaksi setaranya. Persamaan reaksi setara untuk reaksi tersebut sebagai berikut.
 

Mg open parentheses italic s close parentheses and 2 H Cl left parenthesis italic a italic q right parenthesis yields Mg Cl subscript 2 left parenthesis italic a italic q right parenthesis plus H subscript 2 open parentheses italic g close parentheses
 

Jumlah mol gas H subscript 2 yang dihasilkan:

table attributes columnalign right center left columnspacing 0px end attributes row cell mol space Mg end cell equals cell fraction numerator massa space Mg over denominator M subscript r space Mg end fraction end cell row blank equals cell fraction numerator 9 comma 6 space gram over denominator 24 end fraction end cell row blank equals cell 0 comma 4 space mol end cell row blank blank blank row cell mol space H subscript 2 end cell equals cell mol space Mg end cell row blank equals cell 0 comma 4 space mol end cell end table
 

Jumlah molekul gas H subscript 2:
 

table attributes columnalign right center left columnspacing 0px end attributes row cell Jumlah space molekul space H subscript 2 end cell equals cell mol cross times 6 comma 02 cross times 10 to the power of 23 end cell row blank equals cell 0 comma 4 space mol cross times 6 comma 02 cross times 10 to the power of 23 end cell row blank equals cell 2 comma 408 cross times 10 to the power of 23 space end cell end table
 

Jadi, jawaban yang benar adalah D.

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