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Lengkapi dan setarakanlah reaksi redoks berikut de...

Lengkapi dan setarakanlah reaksi redoks berikut dengan metode ion-elektron!

begin mathsize 14px style Cr O subscript 4 to the power of 2 minus sign end exponent subscript open parentheses italic a italic q close parentheses end subscript plus Fe open parentheses O H close parentheses subscript 2 subscript open parentheses italic s close parentheses end subscript rightwards arrow Cr subscript 2 O subscript 3 subscript open parentheses italic s close parentheses end subscript plus Fe open parentheses O H close parentheses subscript 3 subscript open parentheses italic s close parentheses end subscript end style

(suasana basa)

Jawaban:

Untuk menyetarakan reaksi redoks, dapat dilakukan dengan metode ion elektron.

Langkah Sistematis Penyetaraan Setengah Reaksi Redoks Suasana Basa :

begin mathsize 14px style Cr O subscript 4 to the power of 2 minus sign end exponent subscript left parenthesis italic a italic q right parenthesis end subscript plus Fe open parentheses O H close parentheses subscript 2 subscript left parenthesis italic s right parenthesis end subscript rightwards arrow Cr subscript 2 O subscript 3 subscript left parenthesis italic s right parenthesis end subscript plus Fe open parentheses O H close parentheses subscript 3 subscript left parenthesis italic s right parenthesis end subscript end style 

1) Tulis reaksi menjadi 2 bagian reaksi (reduksi - oksidasi).

begin mathsize 14px style Reduksi space colon Cr O subscript 4 to the power of 2 minus sign end exponent subscript left parenthesis italic a italic q right parenthesis end subscript rightwards arrow Cr subscript 2 O subscript 3 subscript left parenthesis italic s right parenthesis end subscript Oksidasi space colon space Fe open parentheses O H close parentheses subscript 2 subscript left parenthesis italic s right parenthesis end subscript yields Fe open parentheses O H close parentheses subscript 3 subscript left parenthesis italic s right parenthesis end subscript end style

2) Setarakan jumlah atom selain begin mathsize 14px style H forward slash space O end style dengan menambahkan koefisien reaksi.

begin mathsize 14px style Reduksi space colon 2 Cr O subscript 4 to the power of 2 minus sign end exponent subscript left parenthesis italic a italic q right parenthesis end subscript rightwards arrow Cr subscript 2 O subscript 3 subscript left parenthesis italic s right parenthesis end subscript Oksidasi space colon space Fe open parentheses O H close parentheses subscript 2 subscript left parenthesis italic s right parenthesis end subscript yields Fe open parentheses O H close parentheses subscript 3 subscript left parenthesis italic s right parenthesis end subscript end style 

3) Setarakan jumlah atom begin mathsize 14px style O end style dengan menambahkan begin mathsize 14px style H subscript 2 O end style pada ruas yang kekurangan begin mathsize 14px style O end style.

begin mathsize 14px style Reduksi space colon 2 Cr O subscript 4 to the power of 2 minus sign end exponent subscript left parenthesis italic a italic q right parenthesis end subscript rightwards arrow Cr subscript 2 O subscript 3 subscript left parenthesis italic s right parenthesis end subscript plus 5 H subscript 2 O subscript open parentheses italic l close parentheses end subscript Oksidasi space colon space Fe open parentheses O H close parentheses subscript 2 subscript left parenthesis italic s right parenthesis end subscript plus H subscript 2 O subscript open parentheses italic l close parentheses end subscript yields Fe open parentheses O H close parentheses subscript 3 subscript left parenthesis italic s right parenthesis end subscript end style

4) Setarakan jumlah atom begin mathsize 14px style H end style dengan menambahkan begin mathsize 14px style H to the power of plus sign end style pada ruas yang kekurangan begin mathsize 14px style H end style.

begin mathsize 14px style Reduksi space colon 2 Cr O subscript 4 to the power of 2 minus sign end exponent subscript left parenthesis italic a italic q right parenthesis end subscript plus 10 H to the power of plus sign subscript open parentheses italic a italic q close parentheses end subscript rightwards arrow Cr subscript 2 O subscript 3 subscript left parenthesis italic s right parenthesis end subscript plus 5 H subscript 2 O subscript left parenthesis italic l right parenthesis end subscript Oksidasi space colon space Fe open parentheses O H close parentheses subscript 2 subscript left parenthesis italic s right parenthesis end subscript plus H subscript 2 O subscript left parenthesis italic l right parenthesis end subscript yields Fe open parentheses O H close parentheses subscript 3 subscript left parenthesis italic s right parenthesis end subscript plus H to the power of plus sign subscript left parenthesis italic a italic q right parenthesis end subscript end style

5) Menetralkan jumlah atom begin mathsize 14px style H to the power of plus sign end style dengan menambahkan sejumlah begin mathsize 14px style O H to the power of minus sign end style pada kedua ruas.

begin mathsize 11px style Reduksi space colon 2 Cr O subscript 4 to the power of 2 minus sign end exponent subscript left parenthesis italic a italic q right parenthesis end subscript plus 10 H to the power of plus sign subscript open parentheses italic a italic q close parentheses end subscript plus 10 O H to the power of minus sign subscript open parentheses italic a italic q close parentheses end subscript rightwards arrow Cr subscript 2 O subscript 3 subscript left parenthesis italic s right parenthesis end subscript plus 5 H subscript 2 O subscript left parenthesis italic l right parenthesis end subscript plus 10 O H to the power of minus sign subscript left parenthesis italic a italic q right parenthesis end subscript Oksidasi space colon Fe open parentheses O H close parentheses subscript 2 subscript left parenthesis italic s right parenthesis end subscript plus H subscript 2 O subscript left parenthesis italic l right parenthesis end subscript plus O H to the power of minus sign subscript left parenthesis italic a italic q right parenthesis end subscript yields Fe open parentheses O H close parentheses subscript 3 subscript left parenthesis italic s right parenthesis end subscript plus H to the power of plus sign subscript left parenthesis italic a italic q right parenthesis end subscript plus O H to the power of minus sign subscript left parenthesis italic a italic q right parenthesis end subscript end style 

6) Menggabungkan begin mathsize 14px style H to the power of plus sign end style dengan begin mathsize 14px style O H to the power of minus sign end style bila ada dalam satu ruas menjadi begin mathsize 14px style H subscript 2 O end style.

begin mathsize 12px style Reduksi space colon 2 Cr O subscript 4 to the power of 2 minus sign end exponent subscript left parenthesis italic a italic q right parenthesis end subscript plus 10 H subscript 2 O subscript open parentheses italic l close parentheses end subscript rightwards arrow Cr subscript 2 O subscript 3 subscript left parenthesis italic s right parenthesis end subscript plus 5 H subscript 2 O subscript left parenthesis italic l right parenthesis end subscript plus 10 O H to the power of minus sign subscript left parenthesis italic a italic q right parenthesis end subscript Oksidasi space colon Fe open parentheses O H close parentheses subscript 2 subscript left parenthesis italic s right parenthesis end subscript plus H subscript 2 O subscript left parenthesis italic l right parenthesis end subscript plus O H to the power of minus sign subscript left parenthesis italic a italic q right parenthesis end subscript yields Fe open parentheses O H close parentheses subscript 3 subscript left parenthesis italic s right parenthesis end subscript plus H subscript 2 O subscript left parenthesis italic l right parenthesis end subscript end style

7) Mengeliminasi begin mathsize 14px style H subscript 2 O end style bila muncul pada kedua ruas.

begin mathsize 12px style Reduksi space colon 2 Cr O subscript 4 to the power of 2 minus sign end exponent subscript left parenthesis italic a italic q right parenthesis end subscript plus 5 H subscript 2 O subscript open parentheses italic a italic q close parentheses end subscript rightwards arrow Cr subscript 2 O subscript 3 subscript left parenthesis italic s right parenthesis end subscript plus 10 O H to the power of minus sign subscript left parenthesis italic a italic q right parenthesis end subscript Oksidasi space colon Fe open parentheses O H close parentheses subscript 2 subscript left parenthesis italic s right parenthesis end subscript plus O H to the power of minus sign subscript left parenthesis italic a italic q right parenthesis end subscript yields Fe open parentheses O H close parentheses subscript 3 subscript left parenthesis italic s right parenthesis end subscript end style

8) Setarakan jumlah muatan dengan menambahkan sejumlah begin mathsize 14px style e with bar on top end style pada ruas yang muatannya sedikit.

begin mathsize 12px style Reduksi space colon 2 Cr O subscript 4 to the power of 2 minus sign end exponent subscript left parenthesis italic a italic q right parenthesis end subscript plus 5 H subscript 2 O subscript left parenthesis italic a italic q right parenthesis end subscript plus 6 e with bar on top rightwards arrow Cr subscript 2 O subscript 3 subscript left parenthesis italic s right parenthesis end subscript plus 10 O H to the power of minus sign subscript left parenthesis italic a italic q right parenthesis end subscript Oksidasi space colon Fe open parentheses O H close parentheses subscript 2 subscript left parenthesis italic s right parenthesis end subscript plus O H to the power of minus sign subscript left parenthesis italic a italic q right parenthesis end subscript yields Fe open parentheses O H close parentheses subscript 3 subscript left parenthesis italic s right parenthesis end subscript plus e with bar on top end style

9) Samakan muatan  begin mathsize 14px style e with bar on top end style

begin mathsize 12px style Reduksi space colon 2 Cr O subscript 4 to the power of 2 minus sign end exponent subscript left parenthesis italic a italic q right parenthesis end subscript plus 5 H subscript 2 O subscript left parenthesis italic a italic q right parenthesis end subscript plus 6 e with bar on top rightwards arrow Cr subscript 2 O subscript 3 subscript left parenthesis italic s right parenthesis end subscript plus 10 O H to the power of minus sign subscript left parenthesis italic a italic q right parenthesis end subscript Oksidasi space colon 6 Fe open parentheses O H close parentheses subscript 2 subscript left parenthesis italic s right parenthesis end subscript plus 6 O H to the power of minus sign subscript left parenthesis italic a italic q right parenthesis end subscript yields 6 Fe open parentheses O H close parentheses subscript 3 subscript left parenthesis italic s right parenthesis end subscript plus stack 6 e with bar on top end style

10) Setarakan reaksi akhir :

Maka, reaksi setara adalah 

begin mathsize 12px style 2 Cr O subscript 4 to the power of 2 minus sign end exponent subscript left parenthesis italic a italic q right parenthesis end subscript plus 6 Fe open parentheses O H close parentheses subscript 2 subscript left parenthesis italic s right parenthesis end subscript plus 5 H subscript 2 O subscript left parenthesis italic l right parenthesis end subscript yields Cr subscript 2 O subscript 3 subscript left parenthesis italic s right parenthesis end subscript plus 6 Fe open parentheses O H close parentheses subscript 3 subscript left parenthesis italic s right parenthesis end subscript plus 4 O H to the power of minus sign subscript open parentheses i close parentheses end subscript end style  

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