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Larutan HCOOH x M (Ka = ) menghasilkan warna yang sama dengan larutan H2SO4 0,005 M bila ditetesi indikator tertentu. Maka harga x adalah ...

Pertanyaan

Larutan HCOOH x M (Ka = begin mathsize 14px style 2 cross times 10 to the power of negative sign 4 end exponent end style) menghasilkan warna yang sama dengan larutan H2SO4 0,005 M bila ditetesi indikator tertentu. Maka harga x adalah ...

  1. 0,1 M

  2. 0,2 Mundefined

  3. 0,3 Mundefined

  4. 0,4 Mundefined

  5. 0,5 Mundefined

Pembahasan Soal:

warna sama menunjukan nilai pH sama sehingga konsentrasi [H+] juga akan sama.

menentukan [H+] dari asam kuat H2SO4 :

begin mathsize 14px style H subscript 2 S O subscript 4 yields 2 H to the power of plus sign and S O subscript 4 to the power of 2 minus sign end exponent space left parenthesis valensi space asam space equals 2 right parenthesis open square brackets H to the power of plus sign close square brackets equals valensi space asam space cross times M open square brackets H to the power of plus sign close square brackets equals 2 space cross times space 0 comma 005 open square brackets H to the power of plus sign close square brackets equals 2 space cross times space 5 cross times 10 to the power of negative sign 3 end exponent open square brackets H to the power of plus sign close square brackets equals 10 to the power of negative sign 2 end exponent  end style 

menentukan kosentrasi HCOOH asam lemah:

begin mathsize 14px style open square brackets H to the power of plus sign close square brackets space space space space space equals square root of Ka cross times M end root open square brackets 10 to the power of negative sign 2 end exponent close square brackets space space equals square root of 2 cross times 10 to the power of negative sign 4 end exponent cross times M end root open square brackets 10 to the power of negative sign 2 end exponent close square brackets squared equals 2 cross times 10 to the power of negative sign 4 end exponent cross times M 10 to the power of negative sign 4 end exponent space space space space equals 2 cross times 10 to the power of negative sign 4 end exponent M space space space space space space space space space space equals fraction numerator up diagonal strike 10 to the power of negative sign 4 end exponent end strike over denominator 2 cross times up diagonal strike 10 to the power of negative sign 4 end exponent end strike end fraction M space space space space space space space space space space equals 0 comma 5 space M end style 

Jadi, jawaban benar adalah E.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 04 April 2021

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