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Larutan 100 mL  1 M dicampur dengan larutan 100 mL...

Larutan 100 mL begin mathsize 14px style H subscript 2 S O subscript 4 end style 1 M dicampur dengan larutan 100 mL begin mathsize 14px style Ba open parentheses O H close parentheses subscript 2 end style 0,1 M dalam kalorimeter. Campuran tersebut menyebabkan kenaikan suhu sebesar begin mathsize 14px style 5 degree C end style. Jika kalor jenis air begin mathsize 14px style 4 comma 2 space J space g to the power of negative sign 1 end exponent space degree C end styledan massa jenis larutan dianggap begin mathsize 14px style 1 space g space mL to the power of negative sign 1 end exponent end style. Tentukan persamaan termokimianya!undefined 

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Jawaban:

begin mathsize 14px style H subscript 2 S O subscript 4 open parentheses italic a italic q close parentheses plus Ba open parentheses O H close parentheses subscript 2 open parentheses italic a italic q close parentheses space yields Ba S O subscript 4 open parentheses italic s close parentheses and 2 H subscript 2 O space space space space increment H space equals space ? space kJ forward slash mol  increment H space equals space minus sign q subscript rxn increment H space equals minus sign left parenthesis m space. space c space. space increment T right parenthesis increment H space equals minus sign left parenthesis 200 space. space 4 comma 2 space. space 5 right parenthesis increment H space equals minus sign 4200 space J end style 

Reaksi netralisasi tersebut membentuk begin mathsize 14px style H subscript 2 O end style sebanyak

begin mathsize 14px style increment H subscript rxn space equals space fraction numerator negative sign q subscript rxn over denominator n subscript H subscript 2 O end subscript end fraction increment H subscript rxn space equals fraction numerator negative sign 4200 space J over denominator 0 comma 02 space mol end fraction increment H subscript rxn space equals minus sign 210 space kJ forward slash mol end style 

 

Berdasarkan penjelasan tersebut, jawaban yang tepat adalah

begin mathsize 14px style H subscript 2 S O subscript 4 open parentheses italic a italic q close parentheses plus Ba open parentheses O H close parentheses subscript 2 open parentheses italic a italic q close parentheses yields Ba S O subscript 4 open parentheses italic s close parentheses and 2 H subscript 2 O open parentheses italic l close parentheses space space space space increment H subscript rxn equals space minus sign 210 space kJ forward slash mol end style.  

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