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Pertanyaan

Kelarutan begin mathsize 14px style Ag Cl end style (begin mathsize 14px style K subscript sp equals 10 to the power of negative sign 10 end exponent end style) dalam larutan undefined 0,0005 M adalah ....begin mathsize 14px style space end style 

S. Hidayati

Master Teacher

Mahasiswa/Alumni Universitas Indonesia

Jawaban terverifikasi

Jawaban

kelarutan begin mathsize 14px style bottom enclose Ag Cl end enclose end style dalam larutan begin mathsize 14px style bottom enclose Ca Cl subscript bold 2 bold space bold 0 bold comma bold 0005 bold space italic M end enclose end style sebesar begin mathsize 14px style bottom enclose bold 10 to the power of bold minus sign bold 7 end exponent bold space italic M end enclose end style.

Pembahasan

begin mathsize 14px style stack Ca Cl subscript 2 with 0 comma 0005 space M below rightwards arrow stack Ca to the power of 2 plus sign with 0 comma 0005 space M below plus stack 2 Cl to the power of minus sign with 0 comma 001 space M below end style 

begin mathsize 14px style Ag with Cl s below rightwards harpoon over leftwards harpoon stack Ag to the power of plus sign with s below plus stack Cl to the power of minus sign with s below end style 

Nilai s jauh lebih kecil dibandingkan 0,001 M.

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript sp space Ag Cl end cell equals cell open square brackets Ag to the power of plus sign close square brackets open square brackets Cl to the power of minus sign close square brackets end cell row cell 10 to the power of negative sign 10 end exponent end cell equals cell open parentheses s close parentheses left parenthesis s plus 0 comma 001 right parenthesis end cell row cell 10 to the power of negative sign 10 end exponent end cell equals cell open parentheses s close parentheses left parenthesis 0 comma 001 right parenthesis end cell row s equals cell fraction numerator 10 to the power of negative sign 10 end exponent over denominator 0 comma 001 end fraction end cell row s equals cell 10 to the power of negative sign 7 end exponent end cell end table end style 


Jadi, kelarutan begin mathsize 14px style bottom enclose Ag Cl end enclose end style dalam larutan begin mathsize 14px style bottom enclose Ca Cl subscript bold 2 bold space bold 0 bold comma bold 0005 bold space italic M end enclose end style sebesar begin mathsize 14px style bottom enclose bold 10 to the power of bold minus sign bold 7 end exponent bold space italic M end enclose end style.

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Diketahui Ksp dari AgCl=1×10−5, berapa gram AgCl yang dapat larut dalam 500 ml larutan MgCl2​ 0,01 M. Jika diketahui Ar Ag = 107,9 ; Cl = 35,45 ....

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