Roboguru

Kelarutan  dalam air adalah sebesar 31 mg/L, maka harga  adalah .... (dik )

Pertanyaan

Kelarutan begin mathsize 14px style Mg F subscript 2 end style dalam air adalah sebesar 31 mg/L, maka harga begin mathsize 14px style K subscript sp space Mg F subscript 2 end style adalah ....undefined (dik begin mathsize 14px style A subscript r space Mg equals 24 comma space F equals 19 end style)

  1. begin mathsize 14px style 5 cross times 10 to the power of negative sign 4 end exponent end style 

  2. begin mathsize 14px style 5 cross times 10 to the power of negative sign 7 end exponent end style 

  3. begin mathsize 14px style 5 cross times 10 to the power of negative sign 9 end exponent end style 

  4. begin mathsize 14px style 5 cross times 10 to the power of negative sign 10 end exponent end style 

  5. begin mathsize 14px style 5 cross times 10 to the power of negative sign 12 end exponent end style 

Pembahasan Soal:

Konversi kelarutan dalam satuan mol/L:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row s equals cell m over M subscript r cross times 1 over V end cell row blank equals cell fraction numerator 0 comma 031 space g over denominator 24 plus left parenthesis 2 cross times 19 right parenthesis space g forward slash mol end fraction cross times fraction numerator 1 over denominator 1 space L end fraction end cell row blank equals cell 5 cross times 10 to the power of negative sign 4 end exponent space mol forward slash L end cell end table end style 
 

begin mathsize 14px style Mg F subscript 2 equilibrium Mg to the power of 2 plus sign and 2 F to the power of minus sign space space space space s space space space space space space space space space space s space space space space space space space space space s end style 


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript sp space Mg F subscript 2 end cell equals cell open square brackets Mg to the power of 2 plus sign close square brackets open square brackets F to the power of minus sign close square brackets squared equals open parentheses s close parentheses left parenthesis 2 s right parenthesis squared equals 4 s cubed end cell row blank equals cell 4 left parenthesis 5 cross times 10 to the power of negative sign 4 end exponent right parenthesis cubed equals 5 cross times 10 to the power of negative sign 10 end exponent end cell end table end style 


Jadi, jawaban yang tepat adalah D.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 03 April 2021

Ruangguru

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ikuti Kami

©2021 Ruangguru. All Rights Reserved