Roboguru

Jika

Pertanyaan

Jika begin mathsize 14px style space to the power of straight p squared plus 4 end exponent log 2 equals fraction numerator space cubed log 5 over denominator space squared log 5. cubed log 8 end fraction comma space dengan space straight p greater than 0 comma space maka space straight p plus to the power of straight p squared end exponent log 16 equals... end style

  1. 0

  2. 1

  3. 2

  4. 3

  5. 4

Pembahasan Soal:

begin mathsize 14px style space to the power of straight p squared plus 4 end exponent log 2 equals fraction numerator space cubed log 5 over denominator space squared log 5. cubed log 8 end fraction  space to the power of straight p squared plus 4 end exponent log 2 equals fraction numerator space cubed log 5 over denominator space cubed log 8. squared log 5 end fraction  space to the power of straight p squared plus 4 end exponent log 2 equals fraction numerator space cubed log 5 over denominator space cubed log 2 cubed. squared log 5 end fraction  space to the power of straight p squared plus 4 end exponent log 2 equals fraction numerator space cubed log 5 over denominator space 3. cubed log up diagonal strike 2. squared end strike log 5 end fraction  space to the power of straight p squared plus 4 end exponent log 2 equals fraction numerator space cubed log 5 over denominator space 3. cubed log 5 end fraction  space to the power of straight p squared plus 4 end exponent log 2 equals fraction numerator space cubed log 5 over denominator space 3. cubed log 5 end fraction  space to the power of straight p squared plus 4 end exponent log 2 equals 1 third  open parentheses straight p squared plus 4 close parentheses to the power of 1 third end exponent equals 2  straight p squared plus 4 equals 2 cubed left right double arrow straight p squared plus 4 equals 8 left right double arrow straight p squared equals 4 left right double arrow straight p equals plus-or-minus 2  Karena space straight p space greater than space 0 comma space maka space nilai space straight p space yang space memenuhi space adalah space straight p space equals space 2 space.  straight p plus to the power of straight p to the power of 2 space end exponent end exponent log 16 equals 2 plus to the power of 2 squared end exponent log 16  space space space space space space space space space space space space space space space space space equals 2 plus to the power of 4 log 16 equals 2 plus 2 equals 4 end style

 

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 22 Desember 2020

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