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Jika variabel acak , nilai  adalah ....

Pertanyaan

Jika variabel acak begin mathsize 14px style straight X tilde straight N open parentheses 60 comma space 20 close parentheses end style, nilai begin mathsize 14px style straight P open parentheses straight X greater than 51 close parentheses end style adalah ....

  1. size 14px 0 size 14px comma size 14px 0054  begin mathsize 14px style space space space end style 

  2. size 14px 0 size 14px comma size 14px 1736   begin mathsize 14px style space space space end style 

  3. size 14px 0 size 14px comma size 14px 3264   begin mathsize 14px style space space space end style 

  4. size 14px 0 size 14px comma size 14px 6735   begin mathsize 14px style space space space end style 

  5. size 14px 0 size 14px comma size 14px 6736   begin mathsize 14px style space space space end style 

Pembahasan Soal:

Diketahui

Variabel acak begin mathsize 14px style straight X tilde straight N open parentheses 60 comma space 20 close parentheses end style, sehingga begin mathsize 14px style straight mu equals 60 end style dan begin mathsize 14px style straight sigma equals 20 end style.

Akan ditentukan nilai begin mathsize 14px style straight P open parentheses straight X greater than 51 close parentheses end style, perhatikan perhitungan berikut:

begin mathsize 14px style table attributes columnalign right center left columnspacing 2px end attributes row cell straight P open parentheses straight X greater than 51 close parentheses end cell equals cell 1 minus straight P open parentheses straight X less than 51 close parentheses end cell row blank equals cell 1 minus straight P open parentheses straight Z less than fraction numerator 51 minus straight mu over denominator straight sigma end fraction close parentheses end cell row blank equals cell 1 minus straight P open parentheses straight Z less than fraction numerator 51 minus 60 over denominator 20 end fraction close parentheses end cell row blank equals cell 1 minus straight P open parentheses straight Z less than fraction numerator negative 9 over denominator 20 end fraction close parentheses end cell row blank equals cell 1 minus straight P open parentheses straight Z less than negative 0 comma 45 close parentheses space space space open parentheses lihat space nilai space pada space tabel space distribusi space straight z close parentheses end cell row blank equals cell 1 minus 0 comma 3264 end cell row cell straight P open parentheses straight X greater than 51 close parentheses end cell equals cell 0 comma 6736 end cell end table end style

Jadi, jawaban yang tepat adalah E.

 

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 12 Februari 2021

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