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Pertanyaan

Jika ∣ lo g g ( x ) ∣ < 1 maka ...

Jika  maka ...

  1. g left parenthesis x right parenthesis less than 0 

  2. g left parenthesis x right parenthesis less than 1 

  3. negative 1 less than g left parenthesis x right parenthesis less than 1 

  4. g left parenthesis x right parenthesis less than 10 

  5. 0 comma 1 less than g left parenthesis x right parenthesis less than 10 

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D. Rajib

Master Teacher

Mahasiswa/Alumni Universitas Muhammadiyah Malang

Jawaban terverifikasi

Jawaban

jawaban yang benar adalah E.

jawaban yang benar adalah E.

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Pembahasan

Diketahui : Ingat kembali bahwa : Misal : maka Syarat (i) Syarat (ii) Jadi, penyelesaiannya adalah irisan dari dengan yaitu . Oleh karena itu, jawaban yang benar adalah E.

Diketahui : open vertical bar log space g left parenthesis x right parenthesis close vertical bar less than 1

Ingat kembali bahwa :

bullet space open vertical bar straight x close vertical bar less than straight a comma space straight a greater than 0 rightwards arrow negative straight a space less than straight x less than straight a bullet space log presuperscript straight a space straight f left parenthesis straight x right parenthesis greater than log presuperscript straight a space straight b comma space straight a greater than 1 rightwards arrow straight f left parenthesis straight x right parenthesis greater than straight b greater than 0 bullet space log presuperscript straight a space straight f left parenthesis straight x right parenthesis less than log presuperscript straight a space straight b comma space straight a greater than 1 rightwards arrow 0 less than straight f left parenthesis straight x right parenthesis less than straight b  

Misal : log space g left parenthesis x right parenthesis equals x maka

table attributes columnalign right center left columnspacing 0px end attributes row cell open vertical bar log space g left parenthesis x right parenthesis close vertical bar end cell less than 1 row cell negative 1 end cell less than cell log space g left parenthesis x right parenthesis less than 1 end cell end table 

Syarat (i) log space g left parenthesis x right parenthesis greater than negative 1  

table attributes columnalign right center left columnspacing 0px end attributes row cell log space g left parenthesis x right parenthesis end cell greater than cell negative 1 end cell row cell log space g left parenthesis x right parenthesis end cell greater than cell log space 10 to the power of negative 1 end exponent end cell row cell log space g left parenthesis x right parenthesis end cell greater than cell log space 1 over 10 end cell row cell g left parenthesis x right parenthesis end cell greater than cell 1 over 10 end cell row cell g left parenthesis x right parenthesis end cell greater than cell 0 comma 1 end cell end table   

Syarat (ii) log space g left parenthesis x right parenthesis less than 1 

table attributes columnalign right center left columnspacing 0px end attributes row cell log space g left parenthesis x right parenthesis end cell less than 1 row cell log space g left parenthesis x right parenthesis end cell less than cell log space 10 end cell row cell g left parenthesis x right parenthesis end cell less than 10 end table 

Jadi, penyelesaiannya adalah irisan dari g left parenthesis x right parenthesis greater than 0 comma 1 dengan g left parenthesis x right parenthesis less than 10 yaitu 0 comma 1 less than g left parenthesis x right parenthesis less than 10.

Oleh karena itu, jawaban yang benar adalah E.

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