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Jika larutan jenuh  mengandung M, Ksp untuk zat in...

Jika larutan jenuh begin mathsize 14px style La subscript 2 open parentheses C subscript 2 O subscript 4 close parentheses subscript 3 end style mengandung begin mathsize 14px style 1 comma 1 cross times 10 to the power of negative sign 6 end exponent end styleM, Ksp untuk zat ini adalah undefined 

  1. begin mathsize 14px style 1 comma 2 cross times 10 to the power of negative sign 12 end exponent end style 

  2. begin mathsize 14px style 1 comma 6 cross times 10 to the power of negative sign 34 end exponent end style 

  3. begin mathsize 14px style 1 comma 7 cross times 10 to the power of negative sign 28 end exponent end style 

  4. begin mathsize 14px style 5 comma 2 cross times 10 to the power of negative sign 30 end exponent end style 

  5. begin mathsize 14px style 1 comma 6 cross times 10 to the power of negative sign 12 end exponent end style 

Jawaban:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell La subscript 2 open parentheses C subscript 2 O subscript 4 close parentheses subscript 3 italic left parenthesis italic s italic right parenthesis italic space end cell rightwards arrow over leftwards arrow cell space 2 La to the power of 3 plus sign italic left parenthesis italic a italic q italic right parenthesis plus 3 C subscript 2 O subscript 4 to the power of 2 minus sign end exponent italic left parenthesis italic a italic q italic right parenthesis end cell row blank blank cell space space space space space space space space s space space space space space space space space space space space space space space space space space space space space space space space 2 s space space space space space space space space space space space space space space space space space space space space 3 s end cell row cell K subscript sp end cell equals cell open square brackets La to the power of 3 plus sign close square brackets squared space space left square bracket C subscript 2 O subscript 4 to the power of 2 minus sign end exponent right square bracket cubed space space end cell row blank equals cell left parenthesis 2 s right parenthesis squared space middle dot space left parenthesis 3 s right parenthesis cubed end cell row blank equals cell 108 s to the power of 5 end cell row blank equals cell 108 left parenthesis 1 comma 1 cross times 10 to the power of negative sign 6 end exponent right parenthesis to the power of 5 equals 1 comma 7 cross times 10 to the power of negative sign 28 end exponent end cell end table end style 

Jadi, jawaban yang benar adalah (C).

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