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Jika konsentrasi dalam larutan jenuh = , maka hasil kali kelarutan ....

Jika konsentrasi begin mathsize 14px style Ca to the power of 2 plus sign end style dalam larutan jenuh begin mathsize 14px style Ca F subscript 2 end style = begin mathsize 14px style 2 cross times 10 to the power of negative sign 4 end exponent space mol forward slash L end style, maka hasil kali kelarutan begin mathsize 14px style Ca F subscript 2 end style ....

Jawaban:

begin mathsize 14px style Ca F subscript 2 open parentheses s close parentheses equilibrium Ca to the power of 2 plus sign open parentheses aq close parentheses and 2 F to the power of minus sign open parentheses aq close parentheses s space space space space space space space space space space space space space space space space space s space space space space space space space space space space space space space space space space space space space 2 s K subscript sp equals open square brackets Ca to the power of 2 plus sign close square brackets open square brackets F to the power of minus sign close square brackets squared K subscript sp double bond open parentheses s close parentheses open parentheses 2 s close parentheses squared K subscript sp equals 4 s cubed K subscript sp equals 4 open parentheses 2 cross times 10 to the power of negative sign 4 end exponent close parentheses cubed K subscript sp equals 3 comma 2 cross times 10 to the power of negative sign 11 end exponent end style

Dengan demikian, maka jawaban yang tepat adalah sesuai penjelasan di atas.

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