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Jika kelarutan  dalam air adalah , kelarutan  dala...

Jika kelarutan Fe open parentheses O H close parentheses subscript 3 dalam air adalah 1 comma 4 cross times 10 to the power of negative sign 10 end exponent, kelarutan Fe open parentheses O H close parentheses subscript 3 dalam larutan Fe Cl subscript 3 0,01 M adalah ...

  1. 1 comma 14 cross times 10 to the power of negative sign 12 end exponent 

  2. 3 comma 37 cross times 10 to the power of negative sign 13 end exponent 

  3. 3 comma 15 cross times 10 to the power of negative sign 15 end exponent 

  4. 1 comma 51 cross times 10 to the power of negative sign 16 end exponent 

  5. 1 comma 32 cross times 10 to the power of negative sign 17 end exponent 

Jawaban:

Menentukan rumus K subscript sp space Fe open parentheses O H close parentheses subscript 3:

Fe open parentheses O H close parentheses subscript 3 yields Fe to the power of 3 plus sign and 3 O H to the power of minus sign 

table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript sp space Fe open parentheses O H close parentheses subscript 3 end cell equals cell open square brackets Fe to the power of 3 plus sign close square brackets open square brackets O H to the power of minus sign close square brackets cubed end cell row blank equals cell s cross times open parentheses 3 s close parentheses cubed end cell row blank equals cell 27 s to the power of 4 end cell row blank equals cell 27 cross times left parenthesis 1 comma 4 cross times 10 to the power of negative sign 10 end exponent right parenthesis to the power of 4 end cell row blank equals cell 27 cross times 3 comma 84 cross times 10 to the power of negative sign 40 end exponent end cell row blank equals cell 103 comma 68 cross times 10 to the power of negative sign 40 end exponent end cell end table 

Sehingga kelarutan Fe open parentheses O H close parentheses subscript 3 dalam larutan Fe Cl subscript 3:

table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript sp space Fe open parentheses O H close parentheses subscript 3 end cell equals cell open square brackets Fe to the power of 3 plus sign close square brackets open square brackets O H to the power of minus sign close square brackets cubed end cell row cell 103 comma 68 cross times 10 to the power of negative sign 40 end exponent end cell equals cell 0 comma 01 cross times open square brackets O H to the power of minus sign close square brackets cubed end cell row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell cube root of 103 comma 68 cross times 10 to the power of negative sign 39 end exponent end root end cell row blank equals cell 1 comma 01 cross times 10 to the power of negative sign 12 end exponent end cell end table 

 Error converting from MathML to accessible text. 

Maka kelarutan Fe open parentheses O H close parentheses subscript 3 dalam larutan Fe Cl subscript 3 adalah table attributes columnalign right center left columnspacing 0px end attributes row blank blank 3 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank comma end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 37 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cross times end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 10 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell blank to the power of negative sign 13 end exponent end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank space end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank M end table.

Jadi, jawaban yang benar adalah B.

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