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Jika diketahui:   Maka perubahan entalpi pembakaran gas karbon disulfida menurut reaksi ...

Pertanyaan

Jika diketahui:

C open parentheses italic s close parentheses and 2 S open parentheses italic s close parentheses yields C S subscript 2 open parentheses italic s close parentheses space space space space space space space space space space space space space space space space space space increment H equals 82 comma 35 space kJ S open parentheses italic s close parentheses and O subscript 2 open parentheses italic g close parentheses yields S O subscript 2 open parentheses italic g close parentheses space space space space space space space space space space space space space space space space space increment H equals minus sign 297 comma 62 space kJ C open parentheses italic s close parentheses and O subscript 2 open parentheses italic g close parentheses yields C O subscript 2 open parentheses italic g close parentheses space space space space space space space space space space space space space space space space increment H equals minus sign 408 comma 80 space kJ 

Maka perubahan entalpi pembakaran gas karbon disulfida menurut reaksi ...

C S subscript 2 open parentheses italic s close parentheses and 3 O subscript 2 open parentheses italic g close parentheses yields C O subscript 2 open parentheses italic g close parentheses and 2 S O subscript 2 open parentheses italic g close parentheses   space space space

  1. plus 1086 comma 39 space kJ space space space

  2. negative sign 1086 comma 39 space kJ space space space

  3. plus 92 comma 169 space kJ space space space

  4. negative sign 921 comma 69 space kJ space space space

  5. negative sign 1004 comma 04 space kJ space space space

Pembahasan Soal:

Dari ketiga persamaan termokimia yang diketahui, kita atur sedemikan rupa agar ketika dijumlahkan menjadi persamaan termokimia yang diminta:

1. space space space C open parentheses italic s close parentheses and 2 S open parentheses italic s close parentheses yields C S subscript 2 open parentheses italic s close parentheses space space space space space space space space space space space space space space space space space space increment H equals 82 comma 35 space kJ 2. space space space S open parentheses italic s close parentheses and O subscript 2 open parentheses italic g close parentheses yields S O subscript 2 open parentheses italic g close parentheses space space space space space space space space space space space space space space space space space increment H equals minus sign 297 comma 62 space kJ 3. space space space C open parentheses italic s close parentheses and O subscript 2 open parentheses italic g close parentheses yields C O subscript 2 open parentheses italic g close parentheses space space space space space space space space space space space space space space space space increment H equals minus sign 408 comma 80 space kJ  

Reaksi nomor 1 ditukar posisi produk dan reaktannya, reaksi nomor 2 koefisiennya dikalikan 2, dan reaksi nomor 3 tidak mengalami perubahan. Kemudian reaksi dijumlahkan dengan menghilangkan senyawa yang sama di kanan dan kiri reaksi.

Perubahan entalpi berubah mengikuti perubahan persamaan termokimia.

  • Jika reaksi ditukar, increment H berubah tanda
  • Jika koefisien reaksi dikalikan n, increment H juga dikalikan n

Persamaan termokimianya menjadi:

1. space space space C S subscript 2 open parentheses italic s close parentheses yields up diagonal strike C open parentheses italic s close parentheses end strike plus up diagonal strike 2 S open parentheses italic s close parentheses end strike space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space increment H equals minus sign 82 comma 35 space kJ 2. space space space up diagonal strike 2 S open parentheses italic s close parentheses end strike plus 2 O subscript 2 open parentheses italic g close parentheses yields 2 S O subscript 2 open parentheses italic g close parentheses space space space space space space space space space space space space space space space space space space space space space space increment H equals minus sign 595 comma 24 space kJ bottom enclose 3. space space space up diagonal strike C open parentheses italic s close parentheses end strike plus O subscript 2 open parentheses italic g close parentheses yields C O subscript 2 open parentheses italic g close parentheses space space space space space space space space space space space space space space space space space space space space space space space space space space space space increment H equals minus sign 408 comma 80 space kJ space space space end enclose space space space space space space space space space space C S subscript 2 open parentheses italic s close parentheses and 3 O subscript 2 open parentheses italic g close parentheses yields 2 S O subscript 2 open parentheses italic g close parentheses and C O subscript 2 open parentheses italic g close parentheses space space space space space increment H equals minus sign 1086 comma 39 space kJ 


Jadi, jawaban yang tepat adalah B.space space space

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 10 Juni 2021

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