Roboguru

Jika diketahui fungsi  dan  maka  adalah ....

Jika diketahui fungsi begin mathsize 14px style f open parentheses x close parentheses equals fraction numerator 2 x over denominator x squared minus 4 end fraction end style dan begin mathsize 14px style g open parentheses x close parentheses equals square root of 2 x end root end style maka begin mathsize 14px style open parentheses f ring operator g close parentheses open parentheses x close parentheses end style adalah ....

  1. begin mathsize 14px style fraction numerator square root of x over denominator x minus 2 end fraction end style 

  2. begin mathsize 14px style fraction numerator square root of 2 x end root over denominator x minus 2 end fraction end style 

  3. begin mathsize 14px style fraction numerator x over denominator x minus 2 end fraction end style 

  4. begin mathsize 14px style fraction numerator square root of 2 x end root over denominator x plus 2 end fraction end style 

  5. begin mathsize 14px style fraction numerator 2 over denominator square root of x minus 2 end root end fraction end style 

Jawaban:

Fungsi begin mathsize 14px style f open parentheses x close parentheses equals fraction numerator 2 x over denominator x squared minus 4 end fraction end style dan begin mathsize 14px style g open parentheses x close parentheses equals square root of 2 x end root end style 

Maka,

begin mathsize 14px style open parentheses f ring operator g close parentheses open parentheses x close parentheses equals f open parentheses g open parentheses x close parentheses close parentheses space space space space space space space space space space space space space space equals fraction numerator 2 open parentheses square root of 2 x end root close parentheses over denominator open parentheses square root of 2 x end root close parentheses squared minus 4 end fraction space space space space space space space space space space space space space space equals fraction numerator 2 open parentheses square root of 2 x end root close parentheses over denominator 2 x minus 4 end fraction space space space space space space space space space space space space space space equals fraction numerator down diagonal strike 2 open parentheses square root of 2 x end root close parentheses over denominator down diagonal strike 2 open parentheses x minus 2 close parentheses end fraction space space space space space space space space space space space space space space equals fraction numerator square root of 2 x end root over denominator x minus 2 end fraction end style 

Jadi, jawaban yang tepat adalah B.

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