Roboguru

Jika diketahui  dan , hasil dari  adalah ....

Pertanyaan

Jika diketahui begin mathsize 14px style f open parentheses x close parentheses equals fraction numerator square root of 7 x plus 8 end root over denominator 2 x minus 5 end fraction end style dan begin mathsize 14px style g open parentheses x close parentheses equals x squared plus 1 end style, hasil dari begin mathsize 14px style open parentheses f ring operator g close parentheses open parentheses 4 close parentheses end style adalah ....

Pembahasan Soal:

begin mathsize 14px style f open parentheses x close parentheses equals fraction numerator square root of 7 x plus 8 end root over denominator 2 x minus 5 end fraction end style dan begin mathsize 14px style g open parentheses x close parentheses equals x squared plus 1 end style,

Maka, 

begin mathsize 14px style open parentheses f ring operator g close parentheses open parentheses x close parentheses equals f open parentheses g open parentheses x close parentheses close parentheses space space space space space space space space space space space space space space space equals fraction numerator square root of 7 open parentheses x squared plus 1 close parentheses plus 8 end root over denominator 2 open parentheses x squared plus 1 close parentheses minus 5 end fraction space space space space space space space space space space space space space space space equals fraction numerator square root of 7 x squared plus 7 plus 8 end root over denominator 2 x squared plus 2 minus 5 end fraction space space space space space space space space space space space space space space space equals fraction numerator square root of 7 x squared plus 15 end root over denominator 2 x squared minus 3 end fraction end style

Kemudian subtitusibegin mathsize 14px style x end style dengan begin mathsize 14px style 4 end style seperti berikut:

begin mathsize 14px style open parentheses f ring operator g close parentheses open parentheses 4 close parentheses equals fraction numerator square root of 7 x squared plus 15 end root over denominator 2 x squared minus 3 end fraction space space space space space space space space space space space space space space equals fraction numerator square root of 7 open parentheses 4 close parentheses squared plus 15 end root over denominator 2 open parentheses 4 close parentheses squared minus 3 end fraction space space space space space space space space space space space space space space equals fraction numerator square root of open parentheses 7 cross times 16 close parentheses plus 15 end root over denominator open parentheses 2 cross times 16 close parentheses minus 3 end fraction space space space space space space space space space space space space space space equals fraction numerator square root of 112 plus 15 end root over denominator 32 minus 3 end fraction space space space space space space space space space space space space space space equals fraction numerator square root of 127 over denominator 29 end fraction end style 

Maka, hasil dari begin mathsize 14px style open parentheses f ring operator g close parentheses open parentheses 4 close parentheses end style adalah begin mathsize 14px style fraction numerator square root of 127 over denominator 29 end fraction end style

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 19 Mei 2021

Ruangguru

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ikuti Kami

©2021 Ruangguru. All Rights Reserved