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Jika  dibagi oleh   dan  masing-masing bersisa  da...

Jika begin mathsize 14px style f open parentheses x close parentheses end style dibagi oleh  begin mathsize 14px style x squared minus x end style dan begin mathsize 14px style x squared plus x end style masing-masing bersisa begin mathsize 14px style 5 x plus 1 end style dan begin mathsize 14px style 3 x plus 1 end style, maka bila begin mathsize 14px style f open parentheses x close parentheses end style dibagi begin mathsize 14px style x squared minus 1 end style sisanya adalah ....

  1. begin mathsize 14px style negative 4 x plus 2 end style   

  2. begin mathsize 14px style 4 x plus 2 end style   

  3. begin mathsize 14px style 2 x plus 4 end style   

  4. begin mathsize 14px style 2 x minus 4 end style   

  5. begin mathsize 14px style negative 2 x minus 4 end style   

Jawaban:

Pembaginya kita faktorkan :
 

begin mathsize 14px style table attributes columnalign right center left columnspacing 2px end attributes row cell straight x squared minus straight x end cell equals 0 row cell straight x open parentheses straight x minus 1 close parentheses end cell equals 0 row cell straight x equals 0 end cell blank cell atau space straight x equals 1 end cell row blank blank blank row cell straight x squared plus straight x end cell equals 0 row cell straight x open parentheses straight x plus 1 close parentheses end cell equals 0 row cell straight x equals 0 end cell blank cell atau space straight x equals negative 1 end cell end table end style 
 

Sisa pembagian 


begin mathsize 14px style table attributes columnalign right center left columnspacing 2px end attributes row cell straight f open parentheses 1 close parentheses end cell equals cell 5 straight x plus 1 end cell row blank equals cell 5 open parentheses 1 close parentheses plus 1 end cell row blank equals 6 row blank blank blank row cell straight f open parentheses negative 1 close parentheses end cell equals cell 3 straight x plus 1 end cell row blank equals cell 3 open parentheses negative 1 close parentheses plus 1 end cell row blank equals cell negative 2 end cell end table end style 
 

Sisa pembagian misalnya begin mathsize 14px style straight S open parentheses straight x close parentheses equals ax plus straight b end style :
 

begin mathsize 14px style table attributes columnalign right center left columnspacing 2px end attributes row cell straight s open parentheses 1 close parentheses end cell equals cell straight a plus straight b table row cell table row cell space space equals end cell 6 end table end cell end table... open parentheses pers. space 1 close parentheses end cell row cell straight s open parentheses negative 1 close parentheses end cell equals cell negative straight a plus straight b table row equals cell negative 2 end cell end table... open parentheses pers.2 close parentheses end cell end table end style 

 

Kemudian pers. 1 dan pers. 2 dieliminasi
 

begin mathsize 14px style table attributes columnalign right center left columnspacing 2px end attributes row cell up diagonal strike straight a plus straight b end cell equals 6 row cell up diagonal strike negative straight a end strike plus straight b end cell equals cell negative 2 end cell end table minus negative negative negative negative negative negative space space plus table row cell space space space space space space space 2 straight b end cell equals 4 row cell space space space space space space space space space straight b end cell equals 2 end table end style 
 

Dengan demikian nilai b kita substitusikan ke pers. 1
 

begin mathsize 14px style table attributes columnalign right center left columnspacing 2px end attributes row cell straight a plus straight b end cell equals 6 row cell straight a plus 2 end cell equals 6 row straight a equals 4 end table end style 
 

Jadi, sisanya adalah begin mathsize 14px style straight S open parentheses straight x close parentheses equals ax plus straight b equals 4 straight x plus 2 end style 

Jadi, jawaban yang te[at adalah B

 

 

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