Roboguru

Jika densitas gas tertentu keadaan STP sebesar , h...

Jika densitas gas tertentu keadaan STP sebesar begin mathsize 14px style 1 comma 27 space kg space m to the power of negative sign 3 end exponent end style, harga densitas gas tersebut pada suhu begin mathsize 14px style 30 degree C end style dan tekanan 768 torr adalah ....undefined (diketahui 1 atm = 760 torr)undefined 

  1. begin mathsize 14px style 1 comma 15 space kg space m to the power of negative sign 3 end exponent end style 

  2. begin mathsize 14px style 1 comma 20 space kg space m to the power of negative sign 3 end exponent end style 

  3. begin mathsize 14px style 1 comma 35 space kg space m to the power of negative sign 3 end exponent end style 

  4. begin mathsize 14px style 1 comma 36 space kg space m to the power of negative sign 3 end exponent end style 

  5. begin mathsize 14px style 1 comma 45 space kg space m to the power of negative sign 3 end exponent end style 

Jawaban:

Pada keadaan STP:

Untuk 1 mol senyawa, volume pada keadaan STP sebesar 22,4 L atau sebesar begin mathsize 14px style 0 comma 0224 space m cubed end style.

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row rho equals cell m over V end cell row cell 1 comma 27 space kg space m to the power of negative sign 3 end exponent end cell equals cell fraction numerator m over denominator 0 comma 0224 space m cubed end fraction end cell row m equals cell 0 comma 0284 space kg end cell end table end style 


Pada suhu begin mathsize 14px style bold 30 bold degree C end style dan tekanan 768 torr:

Tekanan 768 torr setara dengan 1,01 atm.

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row V equals cell fraction numerator n cross times R cross times T over denominator P end fraction end cell row blank equals cell fraction numerator 1 space mol cross times 0 comma 082 space L space atm space mol to the power of negative sign 1 end exponent space K to the power of negative sign 1 end exponent cross times left parenthesis 273 plus 30 right parenthesis space K over denominator 1 comma 01 space atm end fraction end cell row blank equals cell 24 comma 6 space L end cell row blank equals cell 0 comma 0246 space m cubed end cell end table end style 
 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row rho equals cell m over V end cell row blank equals cell fraction numerator 0 comma 0284 space kg over denominator 0 comma 0246 space m cubed end fraction end cell row blank equals cell 1 comma 15 space kg space m to the power of negative sign 3 end exponent end cell end table end style 


Jadi, jawaban yang tepat adalah A.

1

Ruangguru

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ikuti Kami

©2021 Ruangguru. All Rights Reserved