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Jika  dan , maka  adalah ...

Pertanyaan

Jika begin mathsize 14px style f open parentheses x close parentheses equals fraction numerator 2 x over denominator x squared minus 4 end fraction end style dan begin mathsize 14px style g open parentheses x close parentheses equals square root of 2 x end root end style, maka begin mathsize 14px style open parentheses f ring operator g close parentheses open parentheses x close parentheses end style adalah ... 

  1. begin mathsize 14px style fraction numerator square root of x over denominator x minus 2 end fraction end style 

  2. begin mathsize 14px style fraction numerator square root of 2 x end root over denominator x plus 2 end fraction end style 

  3. begin mathsize 14px style fraction numerator square root of 2 x end root over denominator x minus 2 end fraction end style 

  4. begin mathsize 14px style fraction numerator 2 over denominator square root of x minus 2 end root end fraction end style 

  5. begin mathsize 14px style fraction numerator x over denominator square root of x minus 2 end root end fraction end style 

Pembahasan Soal:

Fungsi begin mathsize 14px style f open parentheses x close parentheses equals fraction numerator 2 x over denominator x squared minus 4 end fraction end style dan fungsi begin mathsize 14px style g open parentheses x close parentheses equals square root of 2 x end root end style, maka:

begin mathsize 14px style table attributes columnalign center center left end attributes row cell open parentheses f ring operator g close parentheses open parentheses x close parentheses end cell equals cell f open parentheses g open parentheses x close parentheses close parentheses end cell row space equals cell fraction numerator 2 open parentheses square root of 2 x end root close parentheses over denominator open parentheses square root of 2 x end root close parentheses squared minus 4 end fraction end cell row space equals cell fraction numerator 2 square root of 2 x end root over denominator 2 x minus 4 end fraction end cell row space equals cell fraction numerator down diagonal strike 2 square root of 2 x end root over denominator down diagonal strike 2 open parentheses x minus 2 close parentheses end fraction end cell row space equals cell fraction numerator square root of 2 x end root over denominator x minus 2 end fraction end cell end table end style 

Jadi, jawaban yang tepat adalah C.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 12 Februari 2021

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