Iklan

Iklan

Pertanyaan

Jika tan A = 2 dan tan B = 3 ​ , hitunglah: a. tan ( A + B )

Jika  dan , hitunglah:

a. space 

Iklan

A. Armanda

Master Teacher

Mahasiswa/Alumni Universitas Indraprasta PGRI

Jawaban terverifikasi

Jawaban

.

 table attributes columnalign right center left columnspacing 0px end attributes row blank blank tan end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank space end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell open parentheses straight A plus straight B close parentheses end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator negative 8 minus 5 square root of 3 over denominator 11 end fraction end cell end table.

Iklan

Pembahasan

Rumus Penjumlahan Dua Sudut pada Tangen Diketahui dan , maka hasil dari adalah: Jadi, .

Rumus Penjumlahan Dua Sudut pada Tangen

tan space open parentheses alpha plus beta close parentheses equals fraction numerator tan space alpha plus tan space beta over denominator 1 minus tan space alpha times tan space beta end fraction 

Diketahui tan space straight A equals 2 dan tan space straight B equals square root of 3, maka hasil dari tan space open parentheses straight A plus straight B close parentheses adalah:

table attributes columnalign right center left columnspacing 0px end attributes row cell tan space open parentheses straight A plus straight B close parentheses end cell equals cell fraction numerator tan space straight A plus tan space straight B over denominator 1 minus tan space straight A times tan space straight B end fraction end cell row blank equals cell fraction numerator 2 plus square root of 3 over denominator 1 minus 2 times square root of 3 end fraction end cell row blank equals cell fraction numerator 2 plus square root of 3 over denominator 1 minus 2 square root of 3 end fraction cross times fraction numerator 1 plus 2 square root of 3 over denominator 1 plus 2 square root of 3 end fraction end cell row blank equals cell fraction numerator open parentheses 2 plus square root of 3 close parentheses open parentheses 1 plus 2 square root of 3 close parentheses over denominator 1 squared minus open parentheses 2 square root of 3 close parentheses squared end fraction end cell row blank equals cell fraction numerator 2 plus 4 square root of 3 plus square root of 3 plus square root of 3 times 2 square root of 3 over denominator 1 minus 12 end fraction end cell row blank equals cell fraction numerator 8 plus 5 square root of 3 over denominator negative 11 end fraction end cell row blank equals cell fraction numerator negative open parentheses 8 plus 5 square root of 3 close parentheses over denominator 11 end fraction end cell row blank equals cell fraction numerator negative 8 minus 5 square root of 3 over denominator 11 end fraction end cell end table  

Jadi, table attributes columnalign right center left columnspacing 0px end attributes row blank blank tan end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank space end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell open parentheses straight A plus straight B close parentheses end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator negative 8 minus 5 square root of 3 over denominator 11 end fraction end cell end table.

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

3

TERTIANA RAHMAWATI TAMPUBOLON

Ini yang aku cari!

Tariza Cahya Nurjannah

Jawaban tidak sesuai

Iklan

Iklan

Pertanyaan serupa

2. Selesaikan persamaan berikut. 2 tan − 1 ( 1 − t ) ( 1 + t ) ​ − tan − 1 ( 1 − t ) = tan − 1 t − tan − 1 1 − t 2 ​

8

0.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

info@ruangguru.com

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia