Iklan

Iklan

Pertanyaan

Jika A = [ 1 3 ​ 2 − 4 ​ ] carilah nilai k dan m sehingga A 2 = k . A + m . l

Jika   carilah nilai  dan  sehingga

Iklan

N. Puspita

Master Teacher

Jawaban terverifikasi

Iklan

Pembahasan

Pembahasan
lock

Ingat! Pada matriks: Diketahui dan , maka: A 2 ​ = = = ​ [ 1 3 ​ 2 − 4 ​ ] [ 1 3 ​ 2 − 4 ​ ] [ 1 + 6 3 + ( − 12 ) ​ 2 + ( − 8 ) 6 + 16 ​ ] [ 7 − 9 ​ − 6 22 ​ ] ​ , maka: A 2 [ 7 − 9 ​ − 6 22 ​ ] [ 7 − 9 ​ − 6 22 ​ ] [ 7 − 9 ​ − 6 22 ​ ] [ 7 − 9 ​ − 6 22 ​ ] ​ = = = = = ​ k . A + m . l k [ 1 3 ​ 2 − 4 ​ ] + m [ 1 0 ​ 0 1 ​ ] [ k 3 k ​ 2 k − 4 k ​ ] + [ m 0 ​ 0 m ​ ] [ k + m 3 k + 0 ​ 2 k + 0 − 4 k + m ​ ] [ k + m 3 k ​ 2 k − 4 k + m ​ ] ​ 2 k = − 6 k = − 3 k + m = 7 ( − 3 ) + m = 7 m = 10 Jadi , nilai k dan m adalah k = − 3 d an m = 10 .

Ingat!

Pada matriks:

  • A squared equals A cross times A 
  • open square brackets table row a b row c d end table close square brackets open square brackets table row e f row g h end table close square brackets equals open square brackets table row cell a e plus b g end cell cell a f plus b h end cell row cell c e plus d g end cell cell c f plus d h end cell end table close square brackets 
  • I equals open square brackets table row 1 0 row 0 1 end table close square brackets 
  • table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets table row a b row c d end table close square brackets end cell equals cell open square brackets table row e f row g h end table close square brackets end cell row blank rightwards double arrow cell a equals e comma space b equals f comma space c equals g comma space d equals h end cell end table

 

Diketahui A equals open square brackets table row 1 2 row 3 cell negative 4 end cell end table close square brackets dan I equals open square brackets table row 1 0 row 0 1 end table close square brackets, maka:

 

A squared equals k. A plus m. l, maka:

  

 

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

19

Iklan

Iklan

Pertanyaan serupa

Diketahui persamaan matriks: 3 ( 5 y ​ x 4 ​ ) + ( − 6 3 − y ​ x − 4 − 7 ​ ) = ( 9 13 ​ 8 5 ​ ) Nilai 2 x − y adalah ....

43

4.8

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia