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Jika  atom unsur X massanya 3 gram, maka massa atom relatif unsur itu adalah ....

Pertanyaan

Jika 3 comma 01 cross times 10 to the power of 22 atom unsur X massanya 3 gram, maka massa atom relatif unsur itu adalah ....

  1. 9,03space 

  2. 15,05space 

  3. 30space 

  4. 60space 

  5. 120space 

Pembahasan Soal:

n equals fraction numerator N over denominator 6 comma 02 cross times 10 to the power of 23 end fraction n equals fraction numerator 3 comma 01 cross times 10 to the power of 22 over denominator 6 comma 02 cross times 10 to the power of 23 end fraction n equals 0 comma 05 space mol  M subscript r equals fraction numerator 3 space g over denominator 0 comma 05 space mol end fraction M subscript r equals 60 space g forward slash mol

Dengan demikian, maka jawaban yang tepat adalah D.

Pembahasan terverifikasi oleh Roboguru

Dijawab oleh:

A. Budi

Mahasiswa/Alumni Universitas Pendidikan Indonesia

Terakhir diupdate 05 Juni 2021

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Lengkapi tabel berikut ini!

Pembahasan Soal:

Langkah 1: Melengkapi tabel NO

1. Mol NO (n)

    table attributes columnalign right center left columnspacing 0px end attributes row cell n subscript NO end cell equals cell fraction numerator jumlah space partikel subscript NO over denominator L end fraction end cell row blank equals cell fraction numerator 6 comma 02 cross times 10 to the power of 23 space over denominator 6 comma 022 cross times 10 to the power of 23 end fraction end cell row blank equals cell 1 space mol end cell end table


2. Mr NO 

    table attributes columnalign right center left columnspacing 0px end attributes row cell Mr subscript NO end cell equals cell Ar subscript N and Ar subscript O end cell row blank equals cell 14 plus 16 end cell row blank equals cell 30 space begin inline style bevelled gram over mol end style end cell end table


3. Massa NO (m)

    table attributes columnalign right center left columnspacing 0px end attributes row cell m subscript NO end cell equals cell n subscript NO cross times Mr subscript NO end cell row blank equals cell 1 space mol space cross times 30 space begin inline style bevelled gram over mol end style end cell row blank equals cell 30 space gram end cell end table


4. Volume NO (STP)

    table attributes columnalign right center left columnspacing 0px end attributes row cell V subscript NO end cell equals cell n subscript NO cross times 22 comma 4 space begin inline style bevelled L over mol end style end cell row blank equals cell 1 space mol space cross times 22 comma 4 space begin inline style bevelled L over mol end style end cell row blank equals cell 22 comma 4 space L end cell end table


5. Volume NO (27bold degree bold space C, 1 atm)

    table attributes columnalign right center left columnspacing 0px end attributes row cell V subscript NO end cell equals cell n subscript NO cross times 24 space begin inline style bevelled L over mol end style end cell row blank equals cell 1 space mol cross times 24 space begin inline style bevelled L over mol end style end cell row blank equals cell 24 space L end cell end table


Langkah 2: Melangkapi tabel H subscript bold 2 

1. Jumlah partikel H subscript bold 2 (x)

    table attributes columnalign right center left columnspacing 0px end attributes row cell Jumlah space partikel subscript H subscript 2 end subscript end cell equals cell n subscript H subscript 2 end subscript cross times L end cell row blank equals cell 0 comma 1 space mol cross times 6 comma 022 cross times 10 to the power of 23 space partikel end cell row blank equals cell 6 comma 022 cross times 10 to the power of 22 space partikel end cell row blank blank blank end table

2. Mr H subscript bold 2

    table attributes columnalign right center left columnspacing 0px end attributes row cell Mr subscript H subscript 2 end subscript end cell equals cell 2 cross times Ar subscript H end cell row blank equals cell 2 cross times 1 space begin inline style bevelled gram over mol end style end cell row blank equals cell 2 space begin inline style bevelled gram over mol end style end cell end table
 

3. Massa H subscript bold 2

    table attributes columnalign right center left columnspacing 0px end attributes row cell m subscript H subscript 2 end subscript end cell equals cell n subscript H subscript 2 end subscript cross times Mr subscript H subscript 2 end subscript end cell row blank equals cell 0 comma 1 space mol space cross times 2 space begin inline style bevelled gram over mol end style end cell row blank equals cell 0 comma 2 space gram end cell end table


4. Volume H subscript bold 2 (STP)

    table attributes columnalign right center left columnspacing 0px end attributes row cell V subscript H subscript 2 end subscript end cell equals cell n subscript H subscript 2 end subscript cross times 22 comma 4 space begin inline style bevelled L over mol end style end cell row blank equals cell 0 comma 1 space mol space cross times 22 comma 4 space begin inline style bevelled L over mol end style end cell row blank equals cell 2 comma 24 space L end cell end table


5. Volume H subscript bold 2 (27bold degree bold space C, 1 atm)

    table attributes columnalign right center left columnspacing 0px end attributes row cell V subscript H subscript 2 end subscript end cell equals cell n subscript H subscript 2 end subscript cross times 24 space begin inline style bevelled L over mol end style end cell row blank equals cell 0 comma 1 space mol cross times 24 space begin inline style bevelled L over mol end style end cell row blank equals cell 2 comma 4 space L end cell end table


Langkah 3: Melangkapi tabel N H subscript bold 3

1. mol N H subscript bold 3 (n)

    table attributes columnalign right center left columnspacing 0px end attributes row cell n subscript N H subscript 3 end subscript end cell equals cell fraction numerator V subscript STP subscript N H subscript 3 end subscript end subscript over denominator 22 comma 4 space bevelled L over mol end fraction end cell row blank equals cell fraction numerator 4 comma 48 space L over denominator 22 comma 4 space bevelled L over mol end fraction end cell row blank equals cell 0 comma 2 space mol end cell end table
 

2. Jumlah partikel N H subscript bold 3 (x)
     table attributes columnalign right center left columnspacing 0px end attributes row cell Jumlah space partikel subscript N H subscript 3 end subscript end cell equals cell n subscript N H subscript 3 end subscript cross times L end cell row blank equals cell 0 comma 2 space mol cross times 6 comma 022 cross times 10 to the power of 23 space partikel end cell row blank equals cell 1 comma 2 cross times 10 to the power of 23 space partikel end cell end table


3. Mr N H subscript bold 3

    table attributes columnalign right center left columnspacing 0px end attributes row cell Mr subscript N H subscript 3 end subscript end cell equals cell Ar subscript N plus left parenthesis 3 cross times Ar subscript H right parenthesis end cell row blank equals cell 14 space begin inline style bevelled gram over mol end style plus left parenthesis 3 cross times 1 space begin inline style bevelled gram over mol right parenthesis end style end cell row blank equals cell 17 space begin inline style bevelled gram over mol end style end cell end table
 

4. Massa N H subscript bold 3

    table attributes columnalign right center left columnspacing 0px end attributes row cell m subscript N H subscript 3 end subscript end cell equals cell n subscript N H subscript 3 end subscript cross times Mr subscript N H subscript 3 end subscript end cell row blank equals cell 0 comma 2 space mol space cross times 17 space begin inline style bevelled gram over mol end style end cell row blank equals cell 3 comma 4 space gram end cell end table


5. Volume N H subscript bold 3 (27bold degree bold space C, 1 atm)

    table attributes columnalign right center left columnspacing 0px end attributes row cell V subscript N H subscript 3 end subscript end cell equals cell n subscript N H subscript 3 end subscript cross times 24 space begin inline style bevelled L over mol end style end cell row blank equals cell 0 comma 2 space mol cross times 24 space begin inline style bevelled L over mol end style end cell row blank equals cell 4 comma 8 space L end cell end table


Langkah 4: Melangkapi tabel C H subscript 4

1. mol C H subscript 4 (n)

    table attributes columnalign right center left columnspacing 0px end attributes row cell n subscript C H subscript 4 end subscript end cell equals cell fraction numerator V subscript RTP subscript C H subscript 4 end subscript end subscript over denominator 24 space bevelled L over mol end fraction end cell row blank equals cell fraction numerator 12 comma 3 space L over denominator 24 space bevelled L over mol end fraction end cell row blank equals cell 0 comma 5125 space mol end cell end table 
 

2. Jumlah partikel C H subscript 4 (x)
     table attributes columnalign right center left columnspacing 0px end attributes row cell Jumlah space partikel subscript C H subscript 4 end subscript end cell equals cell n subscript C H subscript 4 end subscript cross times L end cell row blank equals cell 0 comma 512 space mol cross times 6 comma 022 cross times 10 to the power of 23 space partikel end cell row blank equals cell 3 comma 08 cross times 10 to the power of 23 space partikel end cell end table


3. Mr C H subscript 4

    table attributes columnalign right center left columnspacing 0px end attributes row cell Mr subscript C H subscript 4 end subscript end cell equals cell Ar subscript C plus left parenthesis 4 cross times Ar subscript H right parenthesis end cell row blank equals cell 12 space begin inline style bevelled gram over mol end style plus left parenthesis 4 cross times 1 space begin inline style bevelled gram over mol right parenthesis end style end cell row blank equals cell 16 space begin inline style bevelled gram over mol end style end cell end table
 

4. Massa C H subscript 4

    table attributes columnalign right center left columnspacing 0px end attributes row cell m subscript C H subscript 4 end subscript end cell equals cell n subscript C H subscript 4 end subscript cross times Mr subscript C H subscript 4 end subscript end cell row blank equals cell 0 comma 512 space mol space cross times 16 space begin inline style bevelled gram over mol end style end cell row blank equals cell 8 comma 2 space gram end cell end table 


5. Volume C H subscript 4 (STP)

    table attributes columnalign right center left columnspacing 0px end attributes row cell V subscript C H subscript 4 end subscript end cell equals cell n subscript C H subscript 4 end subscript cross times 22 comma 4 space begin inline style bevelled L over mol end style end cell row blank equals cell 0 comma 512 space mol cross times 22.4 space begin inline style bevelled L over mol end style end cell row blank equals cell 11 comma 48 space L end cell end table  


Dengan demikian, tabel lengkapnya adalah

0

Roboguru

Unsur boron mempunyai dua isotop di alam, yaitu B-10 dengan kelimpahan 20 % dan B-11 dengan kelimpahan 80 %. Jika massa atom B-10 sebesar 10 sma dan massa atom B-11 sebesar 11 sma, massa atom relatif ...

Pembahasan Soal:

massa B-10 = 10

massa B-11 = 11

table attributes columnalign right center left columnspacing 0px end attributes row cell Ar space B end cell equals cell left parenthesis kelimpahan space B minus sign 10 space x space massa space B minus sign 10 right parenthesis space plus space left parenthesis kelimpahan space B minus sign 11 space x space massa space B minus sign 11 right parenthesis space end cell row blank equals cell left parenthesis 20 space percent sign space x space 10 right parenthesis plus space left parenthesis 80 space percent sign space x space 11 right parenthesis end cell row blank equals cell 2 plus 8 comma 8 end cell row blank equals cell 10 comma 8 end cell end table

Sehingga massa atom relatif boron adalah 10,8.

Jadi, jawaban yang tepat adalah C.

4

Roboguru

Suatu garam sulfat () memiliki massa molekul relatif sebesar 303. Jika diketahui massa atom relatif S = 32 dan O = 16, tentukan massa atom relatif unsur logam tersebut.

Pembahasan Soal:

table attributes columnalign right center left columnspacing 0px end attributes row cell M subscript r space XSO subscript 4 end cell equals cell left parenthesis 1 cross times A subscript r space X right parenthesis plus left parenthesis 1 cross times A subscript r space S right parenthesis plus left parenthesis 4 cross times A subscript r space O right parenthesis end cell row 303 equals cell A subscript r space X plus left parenthesis 1 cross times 32 right parenthesis plus left parenthesis 4 cross times 16 right parenthesis end cell row 303 equals cell A subscript r space X plus 96 end cell row cell A subscript r space X end cell equals 207 end table 


Jadi, massa atom relatif unsur logam tersebut sebesar 207.

0

Roboguru

Massa rata-rata 1 atom unsur X = gram, jika massa 1 atom C -12 =  gram, berapa Ar unsur X ?

Pembahasan Soal:

Massa atom yang diperoleh dari pengukuran merupakan massa atom relatif terhadap atom karbon-12.
 

begin mathsize 14px style Ar space unsur space x equals fraction numerator massa space rata space minus sign space rata space atom over denominator begin display style 1 over 12 end style massa space atom space C minus sign 12 end fraction Ar space unsur space x equals fraction numerator 6 comma 64 space cross times 10 to the power of negative sign 23 end exponent space up diagonal strike gram over denominator begin display style 1 over 12 left parenthesis 19 comma 9 space cross times 10 to the power of negative sign 24 end exponent right parenthesis up diagonal strike gram end style end fraction Ar space unsur space x equals fraction numerator 6 comma 64 space cross times 10 to the power of negative sign 23 end exponent space over denominator begin display style 1 comma 65 space cross times 10 to the power of negative sign 24 end exponent end style end fraction Ar space unsur space x equals 4 comma 02 space cross times 10 to the power of 1 Ar space unsur space x equals 40 comma 2 end style
 

Jadi, Ar unsur X adalah 40,2.

0

Roboguru

DIketahui massa rata-rata 1 atom X adalah  gram, maka besarnya massa atom relatif X adalah ....

Pembahasan Soal:

Massa 1 atom C-12 = 12 s.m.a atau sama dengan begin mathsize 14px style 2 comma 04 cross times 10 to the power of negative sign 23 end exponent space gram end style.


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell Ar space X end cell equals cell fraction numerator massa space rata bond rata space 1 space atom space X over denominator begin display style 1 over 12 end style cross times massa space 1 space atom space C minus sign 12 end fraction end cell row blank equals cell fraction numerator 1 comma 167 cross times 10 to the power of negative sign 22 end exponent over denominator begin display style 1 over 12 end style cross times 2 comma 04 cross times 10 to the power of negative sign 23 end exponent end fraction end cell row blank equals cell fraction numerator 1 comma 167 cross times 10 to the power of negative sign 22 end exponent over denominator 0 comma 17 cross times 10 to the power of negative sign 23 end exponent end fraction end cell row blank equals cell 68 comma 65 end cell end table end style 


Jadi, massa atom relatif X adalah 68,65 g/mol.

0

Roboguru

Roboguru sudah bisa jawab 91.4% pertanyaan dengan benar

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