Roboguru

Jika  adalah ...

Jika begin mathsize 14px style 3 to the power of straight x equals straight p space dan space 3 to the power of straight y equals straight q space dengan space straight p comma straight q greater than 0 comma space maka space nilai space dari space fraction numerator 2 straight x plus straight y over denominator straight x plus straight y end fraction space adalah space... end style adalah ...

  1. 1 plus to the power of pq logp

  2. 1 plus to the power of pq logq

  3. 1 minus to the power of pq log p

  4. 1 minus to the power of pq log q

  5. 1

Jawaban:

begin mathsize 14px style 3 to the power of straight x equals straight p left right double arrow straight x equals cubed logb  3 to the power of straight y equals straight q left right double arrow straight y equals cubed logq  fraction numerator 2 straight x plus straight y over denominator straight x plus straight y end fraction equals fraction numerator 2 left parenthesis cubed logp right parenthesis plus cubed logq over denominator space cubed logp plus cubed logq end fraction  space space space space space space space space space space equals fraction numerator blank cubed logp plus cubed logq over denominator space cubed logp plus cubed logq end fraction  space space space space space space space space space space equals fraction numerator space cubed logp squared. straight q over denominator space cubed logp. straight q end fraction  space space space space space space space space space space equals to the power of pq logp squared straight q  space space space space space space space space space space equals to the power of pq log left parenthesis pq cross times straight p right parenthesis  space space space space space space space space space space equals to the power of pq logpq plus to the power of pq logp equals 1 plus to the power of pq logp  end style

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