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Invers dari  adalah ....

Pertanyaan

Invers dari begin mathsize 14px style f open parentheses x close parentheses equals open parentheses 1 minus x cubed close parentheses to the power of 1 fifth end exponent plus 2 end style adalah ....

Pembahasan Soal:

Dengan menerapkan konsep invers dari suatu fungsi, diperoleh perhitungan sebagai berikut.

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell f open parentheses x close parentheses end cell equals cell open parentheses 1 minus x cubed close parentheses to the power of 1 fifth end exponent plus 2 end cell row y equals cell open parentheses 1 minus x cubed close parentheses to the power of 1 fifth end exponent plus 2 end cell row cell y minus 2 end cell equals cell open parentheses 1 minus x cubed close parentheses to the power of 1 fifth end exponent end cell row cell open parentheses y minus 2 close parentheses to the power of 5 end cell equals cell open parentheses open parentheses 1 minus x cubed close parentheses to the power of 1 fifth end exponent close parentheses to the power of 5 end cell row cell open parentheses y minus 2 close parentheses to the power of 5 end cell equals cell open parentheses 1 minus x cubed close parentheses end cell row cell x cubed end cell equals cell 1 minus open parentheses y minus 2 close parentheses to the power of 5 end cell row x equals cell cube root of 1 minus open parentheses y minus 2 close parentheses to the power of 5 end root end cell row cell f to the power of negative 1 end exponent open parentheses x close parentheses end cell equals cell cube root of 1 minus open parentheses x minus 2 close parentheses to the power of 5 end root end cell end table end style 

Jadi, invers dari begin mathsize 14px style f open parentheses x close parentheses equals open parentheses 1 minus x cubed close parentheses to the power of 1 fifth end exponent plus 2 end style adalah begin mathsize 14px style f to the power of negative 1 end exponent open parentheses x close parentheses equals cube root of 1 minus open parentheses x minus 2 close parentheses to the power of 5 end root end style.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 13 Maret 2021

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