Iklan

Iklan

Pertanyaan

Hitunglah tiap limit fungsi berikut! x → 4 lim ​ 1 − x − 3 ​ x 2 − 16 ​

Hitunglah tiap limit fungsi berikut!

   

  1. ... undefined 

  2. ... undefined 

Iklan

M. Alfi

Master Teacher

Mahasiswa/Alumni Universitas Negeri Semarang

Jawaban terverifikasi

Jawaban

hasil

hasil begin mathsize 14px style limit as x rightwards arrow 4 of fraction numerator x squared minus 16 over denominator 1 minus square root of x minus 3 end root end fraction equals 0 end style  

Iklan

Pembahasan

Gunakan akar sekawan untuk mengerjakan soal berikut Akar sekawan dari adalah Jadi, hasil

Gunakan akar sekawan untuk mengerjakan soal berikut
Akar sekawan dari begin mathsize 14px style 1 minus square root of x minus 3 end root end style adalah begin mathsize 14px style 1 plus square root of italic x minus sign 3 end root end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow 4 of fraction numerator x squared minus 16 over denominator 1 minus square root of x minus 3 end root end fraction end cell equals cell limit as x rightwards arrow 4 of fraction numerator x squared minus 16 over denominator 1 minus square root of x minus 3 end root end fraction cross times fraction numerator 1 plus square root of x minus 3 end root over denominator 1 plus square root of x minus 3 end root end fraction end cell row blank equals cell limit as x rightwards arrow 4 of fraction numerator left parenthesis x squared minus 16 right parenthesis left parenthesis 1 plus square root of x minus 3 end root right parenthesis over denominator 1 minus square root of x minus 3 end root plus square root of x minus 3 end root minus left parenthesis x minus 3 right parenthesis end fraction end cell row blank equals cell limit as x rightwards arrow 4 of fraction numerator left parenthesis x squared minus 16 right parenthesis left parenthesis 1 plus square root of x minus 3 end root right parenthesis over denominator 1 minus x plus 3 end fraction end cell row blank equals cell limit as x rightwards arrow 4 of fraction numerator left parenthesis negative x plus 4 right parenthesis left parenthesis negative x plus 4 right parenthesis left parenthesis 1 plus square root of x minus 3 end root right parenthesis over denominator negative x plus 4 end fraction end cell row blank equals cell limit as x rightwards arrow 4 of left parenthesis negative x plus 4 right parenthesis left parenthesis 1 plus square root of x minus 3 end root right parenthesis end cell row blank equals cell open parentheses negative 4 plus 4 close parentheses open parentheses 1 plus square root of 4 minus 3 end root close parentheses end cell row blank equals cell open parentheses 0 close parentheses open parentheses 1 plus square root of 1 close parentheses end cell row blank equals 0 end table end style 

Jadi, hasil begin mathsize 14px style limit as x rightwards arrow 4 of fraction numerator x squared minus 16 over denominator 1 minus square root of x minus 3 end root end fraction equals 0 end style  

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

1

Iklan

Iklan

Pertanyaan serupa

Tentukan nilai dari x → − 2 lim ​ x + 2 2 x + 13 ​ − x + 11 ​ ​ .

7

4.7

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

info@ruangguru.com

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia