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Hitunglah pH larutan yang dibuat dari 0,01 mol  dalam 2 liter larutan!

Pertanyaan

Hitunglah pH larutan yang dibuat dari 0,01 mol begin mathsize 14px style K O H end style dalam 2 liter larutan!

begin mathsize 14px style left parenthesis A subscript r space K equals 39 comma space O equals 16 comma space H equals 1 right parenthesis end style undefined 

Pembahasan Soal:

Untuk menentukan pH maka harus dicari molaritas begin mathsize 14px style K O H end style terlebih dahulu. 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row M equals cell fraction numerator italic n space K O H over denominator Volume space larutan end fraction end cell row M equals cell fraction numerator 0 comma 01 space mol over denominator 2 space liter end fraction end cell row M equals cell 0 comma 005 space M end cell row M equals cell 5 cross times 10 to the power of negative sign 3 end exponent space M end cell end table end style  

Dalam air undefined terurai menjadi:

begin mathsize 14px style K O H left parenthesis italic a italic q right parenthesis yields K to the power of plus sign left parenthesis italic a italic q right parenthesis plus O H to the power of minus sign left parenthesis italic a italic q right parenthesis end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell 1 over 1 cross times open square brackets K O H close square brackets end cell row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell 1 cross times left parenthesis 5 cross times 10 to the power of negative sign 3 end exponent right parenthesis space M end cell row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell 5 cross times 10 to the power of negative sign 3 end exponent space M end cell row blank blank blank row pOH equals cell negative sign log open square brackets O H to the power of minus sign close square brackets end cell row pOH equals cell negative sign log left square bracket 5 cross times 10 to the power of negative sign 3 end exponent right square bracket end cell row pOH equals cell 3 minus sign log space 5 end cell row blank blank blank row pH equals cell 14 minus sign pOH end cell row pH equals cell 14 minus sign left parenthesis 3 minus sign log space 5 right parenthesis end cell row pH equals cell 11 plus log space 5 end cell end table end style 

Jadi pH KOH adalah undefined.undefined 

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 01 April 2021

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