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Hitunglah pH larutan asam/basa berikut : d.

Pertanyaan

Hitunglah pH larutan asam/basa berikut :

d.  begin mathsize 14px style Larutan space N H subscript 4 O H space 0 comma 001 space M space left parenthesis Kb equals 1 cross times 10 to the power of negative sign 5 end exponent right parenthesis end style

Pembahasan Soal:

Larutan N H subscript 4 O H merupakan basa lemah sehingga perhitungan pH dapat menggunakan persamaan di bawah ini.

table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell square root of Kb cross times M end root end cell row blank equals cell square root of left parenthesis 1 cross times 10 to the power of negative sign 5 end exponent right parenthesis cross times left parenthesis 0 comma 001 space M right parenthesis end root end cell row blank equals cell square root of 1 cross times 10 to the power of negative sign 8 end exponent end root end cell row blank equals cell 1 cross times 10 to the power of negative sign 4 end exponent space end cell row blank blank blank row pOH equals cell negative sign log open square brackets O H to the power of minus sign close square brackets end cell row blank equals cell negative sign log space left parenthesis 1 cross times 10 to the power of negative sign 4 end exponent right parenthesis end cell row blank equals 4 row blank blank blank row cell pH and pOH end cell equals 14 row pH equals cell 14 minus sign pOH end cell row blank equals cell 14 minus sign 4 end cell row blank equals 10 end table

Jadi, pH larutan N H subscript 4 O H 0,001 M adalah 10.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 18 Mei 2021

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