Roboguru

Hitunglah pH larutan   0,01 M (Kb  = 2 x 10-5)!

Hitunglah pH larutan begin mathsize 14px style N H subscript 4 Cl end style  0,01 M (Kb begin mathsize 14px style N H subscript 4 O H end style = 2 x 10-5)!

Jawaban:

begin mathsize 14px style N H subscript 4 Cl end style merupakan garam yang berasal dari asam kuat HCl dan basa lemah NH4OH. Maka garam tersebut memiliki ion H+ yang lebih banyak daripada ion OH- dan biasa disebut garam asam. 

Untuk mencari pH larutannya, maka menggunakan persamaan:

begin mathsize 14px style open square brackets H to the power of plus sign close square brackets space equals space square root of Kw over K subscript b x left square bracket Garam space asam right square bracket end root open square brackets H to the power of plus sign close square brackets space equals space square root of fraction numerator 10 to the power of negative sign 14 end exponent over denominator 2 space x space 10 to the power of negative sign 5 end exponent end fraction space x space 0 comma 01 space M end root open square brackets H to the power of plus sign close square brackets space equals space square root of 5 space x 10 to the power of negative sign 10 end exponent x space 10 to the power of negative sign 2 end exponent end root open square brackets H to the power of plus sign close square brackets space equals space 2 comma 23 space x space 10 to the power of negative sign 6 end exponent  pH space equals space minus sign space log space open square brackets H to the power of plus sign close square brackets pH space equals space minus sign space log space 2 comma 23 space x space 10 to the power of negative sign 6 end exponent pH space equals space 6 space minus sign space log space 2 comma 23 pH space equals space 6 space minus sign space 0 comma 348 pH space equals space 5 comma 652 end style 

Jadi, pH larutan  begin mathsize 14px style N H subscript 4 Cl end style adalah 5,652.

 

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