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Hitunglah pH dari 100 mL larutan  0,1 M jika .

Pertanyaan

Hitunglah pH dari 100 mL larutan begin mathsize 14px style Ca open parentheses N O subscript 2 close parentheses subscript 2 end style 0,1 M jika begin mathsize 14px style K subscript a space H N O subscript 2 equals 5 cross times 10 to the power of negative sign 4 end exponent end style.undefined 

Pembahasan Soal:

begin mathsize 14px style Ca open parentheses N O subscript 2 close parentheses subscript 2 end style merupakan garam yang bersifat basa.

begin mathsize 14px style Ca open parentheses N O subscript 2 close parentheses subscript 2 yields Ca to the power of 2 plus sign plus 2 N O subscript 2 to the power of minus sign end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell square root of K subscript w over K subscript a cross times 2 cross times left square bracket Ca open parentheses N O subscript 2 close parentheses subscript 2 right square bracket end root end cell row blank equals cell square root of fraction numerator 10 to the power of negative sign 14 end exponent over denominator 5 cross times 10 to the power of negative sign 4 end exponent end fraction cross times 2 cross times 10 to the power of negative sign 1 end exponent end root end cell row blank equals cell square root of 4 cross times 10 to the power of negative sign 12 end exponent end root end cell row blank equals cell 2 cross times 10 to the power of negative sign 6 end exponent end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row pOH equals cell negative sign log space open square brackets O H to the power of minus sign close square brackets end cell row blank equals cell negative sign log space left parenthesis 2 cross times 10 to the power of negative sign 6 end exponent right parenthesis end cell row blank equals cell 6 minus sign log space 2 end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row pH equals cell 14 minus sign pOH end cell row blank equals cell 14 minus sign left parenthesis 6 minus sign log space 2 right parenthesis end cell row blank equals cell 8 plus log space 2 end cell end table end style 


Jadi, pH larutan tersebut adalah 8 + log 2.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 15 Maret 2021

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