Iklan

Iklan

Pertanyaan

Hitunglah nilai limit fungsi berikut: x → 1 lim ​ ( x − 1 ) 2 ( 2 x − 3 x ​ + 1 ) ( x ​ − 1 ) ​

Hitunglah nilai limit fungsi berikut:
 

Iklan

B. Hary

Master Teacher

Jawaban terverifikasi

Iklan

Pembahasan

Pembahasan
lock

limit as x rightwards arrow 1 of fraction numerator left parenthesis 2 x minus 3 square root of x plus 1 right parenthesis left parenthesis square root of x minus 1 right parenthesis over denominator open parentheses x minus 1 close parentheses squared end fraction left right double arrow limit as x rightwards arrow 1 of fraction numerator left parenthesis 2 x minus 3 square root of x plus 1 right parenthesis left parenthesis square root of x minus 1 right parenthesis over denominator open parentheses x minus 1 close parentheses open parentheses x minus 1 close parentheses end fraction times fraction numerator square root of x plus 1 over denominator square root of x plus 1 end fraction left right double arrow limit as x rightwards arrow 1 of fraction numerator open parentheses 2 square root of x minus 1 close parentheses open parentheses square root of x minus 1 close parentheses left parenthesis x minus 1 right parenthesis over denominator left parenthesis x minus 1 right parenthesis open parentheses x minus 1 close parentheses open parentheses square root of x plus 1 close parentheses end fraction left right double arrow limit as x rightwards arrow 1 of fraction numerator left parenthesis 2 square root of x minus 1 right parenthesis left parenthesis square root of x minus 1 right parenthesis over denominator open parentheses x minus 1 close parentheses open parentheses square root of x plus 1 close parentheses end fraction left right double arrow limit as x rightwards arrow 1 of fraction numerator left parenthesis 2 square root of x minus 1 right parenthesis left parenthesis square root of x minus 1 right parenthesis over denominator open parentheses square root of x minus 1 close parentheses open parentheses square root of x plus 1 close parentheses open parentheses square root of x plus 1 close parentheses end fraction left right double arrow limit as x rightwards arrow 1 of fraction numerator left parenthesis 2 square root of x minus 1 right parenthesis over denominator open parentheses square root of x plus 1 close parentheses open parentheses square root of x plus 1 close parentheses end fraction equals 1 fourth 

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

73

ratri afiza azfa

Pembahasan lengkap banget Mudah dimengerti Makasih ❤️

Nando Juan

Pembahasan tidak lengkap Jawaban tidak sesuai

Iklan

Iklan

Pertanyaan serupa

Hitunglah nilai dari x → 1 lim ​ 2 − x + 3 ​ x 2 − 2 x + 1 ​ !

1

5.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia