Roboguru

Hitunglah Mr dari zat-zat berikut ini ! d. KAI(SO4)2.12H2O e. K4Fe(CN)6

Pertanyaan

Hitunglah Mr dari zat-zat berikut ini !
d. KAI(SO4)2.12H2O
e. K4Fe(CN)6

Pembahasan Soal:

d. menentukan Mr KAI(SO4)2.12H2O:

begin mathsize 14px style Ar space K space equals space 39 space Ar space Al space equals space 27 space Ar space H space equals space 1 space Ar space O space equals space 16 space Ar space S space equals space 32 Mr space K Al open parentheses S O subscript 4 close parentheses subscript 2.12 H subscript 2 O equals space Ar space K space plus space Ar space Al space plus space left parenthesis 2 cross times Ar space S right parenthesis space plus space left parenthesis 20 cross times Ar space O right parenthesis space plus space left parenthesis 24 cross times Ar space H right parenthesis space Mr space K Al open parentheses S O subscript 4 close parentheses subscript 2.12 H subscript 2 O equals space 39 space plus space 27 space plus space left parenthesis 2 cross times 32 right parenthesis space plus space left parenthesis 20 cross times 16 right parenthesis space plus space left parenthesis 24 cross times 1 right parenthesis space Mr space K Al open parentheses S O subscript 4 close parentheses subscript 2.12 H subscript 2 O equals space 39 space plus space 27 space plus space 64 space plus space 320 space plus space 24 Mr space K Al open parentheses S O subscript 4 close parentheses subscript 2.12 H subscript 2 O space equals 474 end style 

d. menentukan Mr K4Fe(CN)6:

begin mathsize 14px style Ar space K equals 39 Ar space Fe equals 56 Ar space C equals 14 Ar space N space equals 12 Mr space K subscript 4 Fe open parentheses C N close parentheses subscript 6 space equals space left parenthesis 4 cross times Ar space K right parenthesis plus left parenthesis Ar space Fe right parenthesis plus left parenthesis 6 cross times Ar space C right parenthesis plus left parenthesis 6 cross times Ar space N right parenthesis Mr space K subscript 4 Fe open parentheses C N close parentheses subscript 6 space equals space left parenthesis 4 cross times 39 right parenthesis plus left parenthesis 56 right parenthesis plus left parenthesis 6 cross times 14 right parenthesis plus left parenthesis 6 cross times 12 right parenthesis Mr space K subscript 4 Fe open parentheses C N close parentheses subscript 6 space equals 156 space plus space 56 space plus space 72 space plus space 84 Mr space K subscript 4 Fe open parentheses C N close parentheses subscript 6 space equals 368   end style 

Jadi, Mr dari KAI(SO4)2.12H2O=474 dan Mr dari K4Fe(CN)6 =368

 

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 12 April 2021

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ikuti Kami

©2021 Ruangguru. All Rights Reserved