Roboguru

Pertanyaan

Himpunan penyelesaian dari pertidaksamaan begin mathsize 14px style open vertical bar x plus 3 close vertical bar greater or equal than 15 minus 2 open vertical bar x plus 3 close vertical bar end style adalah ...

  1. begin mathsize 14px style open curly brackets right enclose x space minus 8 less or equal than x less or equal than negative 2 comma space x element of straight real numbers space close curly brackets end style 

  2. begin mathsize 14px style left curly bracket right enclose x space minus 8 less or equal than x less or equal than 2 comma space x element of straight real numbers space right curly bracket end style 

  3. begin mathsize 14px style open curly brackets right enclose x space x less or equal than negative 8 space atau space x greater or equal than negative 2 comma space x element of straight real numbers space close curly brackets end style 

  4. begin mathsize 14px style left curly bracket right enclose x space x less or equal than negative 8 space atau space x greater or equal than 2 comma space x element of straight real numbers space right curly bracket end style 

  5. begin mathsize 14px style left curly bracket right enclose x space x less or equal than negative 2 space atau space x greater or equal than 8 comma space x element of straight real numbers space right curly bracket end style 

M. Mariyam

Master Teacher

Mahasiswa/Alumni Institut Pertanian Bogor

Jawaban terverifikasi

Pembahasan

Himpunan penyelesaian dari pertidaksamaan begin mathsize 14px style open vertical bar x plus 3 close vertical bar greater or equal than 15 minus 2 open vertical bar x plus 3 close vertical bar end style adalah

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open vertical bar x plus 3 close vertical bar end cell greater or equal than cell 15 minus 2 open vertical bar x plus 3 close vertical bar end cell row cell open vertical bar x plus 3 close vertical bar plus 2 open vertical bar x plus 3 close vertical bar end cell greater or equal than 15 row cell 3 open vertical bar x plus 3 close vertical bar end cell greater or equal than 15 row cell open vertical bar x plus 3 close vertical bar end cell greater or equal than cell 15 over 3 end cell row cell open vertical bar x plus 3 close vertical bar end cell greater or equal than 5 end table end style 

Kita harus mengingat sifat pertidaksamaan mutlak berikut:

begin mathsize 14px style open vertical bar f open parentheses x close parentheses close vertical bar greater or equal than a left right arrow f open parentheses x close parentheses less or equal than negative a space atau space f open parentheses x close parentheses greater or equal than a end style

Dengan demikian,

begin mathsize 14px style open vertical bar x plus 3 close vertical bar greater or equal than 5 left right arrow open curly brackets right enclose x x plus 3 less or equal than negative 5 space atau space x plus 3 greater or equal than 5 space comma space x element of straight real numbers close curly brackets left right arrow open curly brackets right enclose x x less or equal than negative 5 minus 3 space atau space x greater or equal than 5 minus 3 comma space x element of straight real numbers close curly brackets left right arrow open curly brackets right enclose x x less or equal than negative 8 space space atau space x greater or equal than 2 comma space x element of straight real numbers close curly brackets end style 

Jadi, jawaban yang tepat adalah D.

 

 

 

 

 

104

0.0 (0 rating)

Pertanyaan serupa

Tentukan himpunan penyelesaian pertidaksamaan dari !

161

0.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ruangguru WhatsApp

081578200000

Email info@ruangguru.com

info@ruangguru.com

Contact 02140008000

02140008000

Ikuti Kami

©2022 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia