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Himpunan penyelesaian dari ( 8 1 ​ ) 8 + 2 x − x 2 ≤ ( 16 1 ​ ) x + 2 adalah...

Himpunan penyelesaian dari adalah...

  1. open curly brackets x vertical line x less or equal than negative 3 space atau space straight x greater or equal than 2 close curly brackets

  2. open curly brackets x vertical line x less or equal than negative 3 space atau space straight x greater or equal than 3 over 8 close curly brackets

  3. open curly brackets x vertical line x less or equal than negative 2 space atau space straight x greater or equal than 3 over 8 close curly brackets

  4. open curly brackets x vertical line x less or equal than 3 over 8 space atau space straight x greater or equal than 3 over 8 close curly brackets

  5. open curly brackets x vertical line x less or equal than 2 space atau space straight x greater or equal than 3 over 8 close curly brackets

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M. Nasrullah

Master Teacher

Mahasiswa/Alumni Universitas Negeri Makassar

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Pembahasan

Ingat bahwa pentuk pertidaksamaan eksponen: Sehingga diperoleh perhitungan: titik uji Sehingga himpunanan penyelesaiannya Jadi, tidak ada jawaban yang tepat

Ingat bahwa pentuk pertidaksamaan eksponen:

a to the power of f open parentheses x close parentheses end exponent less or equal than a to the power of g open parentheses x close parentheses end exponent rightwards arrow f open parentheses x close parentheses less or equal than g open parentheses x close parentheses 

Sehingga diperoleh perhitungan:

table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses 1 over 8 close parentheses to the power of 8 plus 2 x minus x squared end exponent end cell less or equal than cell open parentheses 1 over 16 close parentheses to the power of x plus 2 end exponent end cell row cell open parentheses 2 to the power of negative 3 end exponent close parentheses to the power of 8 plus 2 x minus x squared end exponent end cell less or equal than cell open parentheses 2 to the power of negative 4 end exponent close parentheses to the power of x plus 2 end exponent end cell row cell 2 to the power of negative 3 open parentheses 8 plus 2 x minus x squared close parentheses end exponent end cell less or equal than cell 2 to the power of negative 4 open parentheses x plus 2 close parentheses end exponent end cell row cell 2 to the power of negative 24 minus 6 x plus 3 x squared end exponent end cell less or equal than cell 2 to the power of negative 4 x minus 8 end exponent end cell row blank blank blank row blank rightwards double arrow cell negative 24 minus 6 x plus 3 x squared less or equal than negative 4 x minus 8 end cell row cell negative 24 minus 6 x plus 3 x squared plus 4 x plus 8 end cell less or equal than 0 row cell 3 x squared minus 2 x minus 16 end cell less or equal than 0 row cell open parentheses 3 x minus 8 close parentheses open parentheses x plus 2 close parentheses end cell less or equal than 0 row x equals cell 8 over 3 space atau space straight x equals negative 2 end cell row blank blank blank end table 

titik uji x equals 0

table attributes columnalign right center left columnspacing 0px end attributes row cell 3 x squared minus 2 x minus 16 end cell less or equal than 0 row cell open parentheses 0 close parentheses minus open parentheses 0 close parentheses minus 16 end cell less or equal than 0 row cell negative 16 end cell less or equal than cell 0 space open parentheses b e n a r close parentheses end cell end table

Sehingga himpunanan penyelesaiannya open curly brackets x vertical line minus 2 less or equal than x less or equal than 8 over 3 close curly brackets

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Rhea Almanissa

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