Roboguru

Hasil kali kelarutan  dalam air pada suhu tertentu adalah . Tentukan kelarutan  dalam: Larutan  0,1 M ()

Pertanyaan

Hasil kali kelarutan Mg open parentheses O H close parentheses subscript 2 dalam air pada suhu tertentu adalah 2 cross times 10 to the power of negative sign 11 end exponent. Tentukan kelarutan Mg open parentheses O H close parentheses subscript 2 dalam:

Larutan N H subscript 3 0,1 M (K subscript b equals 10 to the power of negative sign 5 end exponent)

Pembahasan Soal:

Penentuan kelarutan Mg open parentheses O H close parentheses subscript 2 dalam larutan N H subscript 3 0,1M dapat dihitung berdasarkan pengaruh ion senama. N H subscript 3 adalah basa lemah sehingga yang dihitung adalah konsentrasi ion O H to the power of minus sign

table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell square root of K subscript b cross times M end root end cell row blank equals cell square root of 10 to the power of negative sign 5 end exponent cross times 0 comma 1 end root end cell row blank equals cell 10 to the power of negative sign 3 end exponent end cell row blank blank blank row cell Mg open parentheses O H close parentheses subscript 2 end cell rightwards harpoon over leftwards harpoon cell Mg to the power of 2 plus sign and 2 O H to the power of minus sign end cell row blank blank cell space space space space s space space space space space space space space space space space space space space s space space space space space space space space space space 2 s end cell row cell K subscript sp end cell equals cell open square brackets Mg to the power of 2 plus sign close square brackets open square brackets O H to the power of minus sign close square brackets squared end cell row cell 2 cross times 10 to the power of negative sign 11 end exponent end cell equals cell s cross times left parenthesis 10 to the power of negative sign 3 end exponent right parenthesis squared 2 cross times 10 to the power of negative sign 11 end exponent equals s cross times 10 to the power of negative sign 6 end exponent end cell row s equals cell fraction numerator 2 cross times 10 to the power of negative sign 11 end exponent over denominator 10 to the power of negative sign 6 end exponent end fraction end cell row blank equals cell 2 cross times 10 to the power of negative sign 5 end exponent end cell end table  

Jadi, kelarutan Mg open parentheses O H close parentheses subscript 2 dalam larutan N H subscript 3 0,1 M adalah Error converting from MathML to accessible text..

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 06 Mei 2021

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ikuti Kami

©2021 Ruangguru. All Rights Reserved