Iklan

Iklan

Pertanyaan

Hasil dari − 7 3 3 q ​ + 5 3 ( 9 q 2 ) 2 1 ​ ​ − 2 ( 3 q ) 3 1 ​ adalah ...

Hasil dari  adalah ...

Iklan

N. Puspita

Master Teacher

Jawaban terverifikasi

Jawaban

.

 negative 7 cube root of 3 q end root plus 5 cube root of open parentheses 9 q squared close parentheses to the power of 1 half end exponent end root minus 2 open parentheses 3 q close parentheses to the power of 1 third end exponent equals table attributes columnalign right center left columnspacing 0px end attributes row blank blank minus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 4 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank space end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell cube root of 3 q end root end cell end table.

Iklan

Pembahasan

Pembahasan
lock

Ingat bahwa: Mencari hasil dari : Jadi, .

Ingat bahwa:

  • left parenthesis a b right parenthesis to the power of n equals a to the power of n end exponent b to the power of n 
  • left parenthesis a to the power of n right parenthesis to the power of m equals a to the power of n space x space m end exponent
  • m-th root of a to the power of n end root equals a to the power of n over m end exponent 

Mencari hasil dari negative 7 cube root of 3 q end root plus 5 cube root of open parentheses 9 q squared close parentheses to the power of 1 half end exponent end root minus 2 left parenthesis 3 q right parenthesis to the power of 1 third end exponent:

table attributes columnalign right center left columnspacing 0px end attributes row cell negative 7 cube root of 3 q end root plus 5 cube root of open parentheses 9 q squared close parentheses to the power of 1 half end exponent end root minus 2 open parentheses 3 q close parentheses to the power of 1 third end exponent end cell equals cell negative 7 cube root of 3 q end root plus 5 cube root of 3 to the power of 2 space x space 1 half end exponent. space q to the power of 2 space x space 1 half end exponent end root minus 2 cube root of 3 q end root end cell row blank equals cell negative 7 cube root of 3 q end root plus 5 thin space cube root of 3 q end root minus 2 cube root of 3 q end root end cell row blank equals cell left parenthesis negative 7 plus 5 minus 2 right parenthesis cube root of 3 q end root end cell row blank equals cell negative 4 space cube root of 3 q end root end cell end table 

Jadi, negative 7 cube root of 3 q end root plus 5 cube root of open parentheses 9 q squared close parentheses to the power of 1 half end exponent end root minus 2 open parentheses 3 q close parentheses to the power of 1 third end exponent equals table attributes columnalign right center left columnspacing 0px end attributes row blank blank minus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 4 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank space end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell cube root of 3 q end root end cell end table.

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

19

Iklan

Iklan

Pertanyaan serupa

Bentuk sederhana dari ( 32 p 2 q − 1 r 6 4 p − 1 q 2 r 3 ​ ) − 1 adalah....

12

4.3

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia