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Hasil dari  adalah ...

Pertanyaan

Hasil dariintegral open parentheses 2 over x minus 3 close parentheses squared space straight d x  adalah ...

  1. negative 4 x to the power of negative 1 end exponent minus 12 ln space x plus 9 x plus C  

  2. 4 x to the power of negative 1 end exponent minus 12 ln space x plus 9 x plus C   

  3. negative 4 x to the power of negative 1 end exponent minus 12 ln space x minus 9 x plus C  

  4. negative 4 x to the power of negative 1 end exponent plus 12 ln space x plus 9 x plus C   

  5. 4 x to the power of negative 1 end exponent minus 12 ln space x minus 9 x plus C   

Pembahasan Soal:

table attributes columnalign right center left columnspacing 0px end attributes row cell integral open parentheses 2 over x minus 3 close parentheses squared space straight d x end cell equals cell integral open parentheses 4 over x squared minus 12 over x plus 9 close parentheses straight d x end cell row blank equals cell integral open parentheses 4 x to the power of negative 2 end exponent minus 12 over x plus 9 close parentheses straight d x end cell row blank equals cell negative 4 x to the power of negative 1 end exponent minus 12 ln space x plus 9 x plus C end cell end table

Jadi, jawaban yang tepat adalah A

Pembahasan terverifikasi oleh Roboguru

Dijawab oleh:

I. Roy

Mahasiswa/Alumni Universitas Negeri Surabaya

Terakhir diupdate 05 Juni 2021

Roboguru sudah bisa jawab 91.4% pertanyaan dengan benar

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Pertanyaan yang serupa

Jika diketahui dengan dan , maka nilai dari a + b adalah….

Pembahasan Soal:

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Roboguru

Diketahui . Nilai dari  adalah ....

Pembahasan Soal:

Integral atau anti turunan memenuhi algoritma berikut

table attributes columnalign right center left columnspacing 0px end attributes row cell size 14px integral subscript size 14px a superscript size 14px b k x to the power of n size 14px d size 14px x end cell size 14px equals cell right enclose fraction numerator size 14px k size 14px x to the power of size 14px n size 14px minus size 14px 1 end exponent over denominator size 14px n size 14px minus size 14px 1 end fraction end enclose subscript size 14px a superscript size 14px b end cell row blank size 14px equals cell fraction numerator size 14px k size 14px b to the power of size 14px n size 14px minus size 14px 1 end exponent over denominator size 14px n size 14px minus size 14px 1 end fraction size 14px minus fraction numerator size 14px k size 14px a to the power of size 14px n size 14px minus size 14px 1 end exponent over denominator size 14px n size 14px minus size 14px 1 end fraction end cell end table

maka

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell integral subscript a superscript 3 open parentheses 3 x squared plus 2 x plus 1 close parentheses d x end cell equals 25 row cell right enclose 3 over 3 x cubed plus 2 over 2 x squared plus x end enclose subscript a superscript 3 end cell equals 25 row cell open parentheses 3 cubed plus 3 squared plus 3 close parentheses minus open parentheses a cubed plus a squared plus a close parentheses end cell equals 25 row cell 39 minus open parentheses a cubed plus a squared plus a close parentheses end cell equals 25 row cell open parentheses a cubed plus a squared plus a close parentheses end cell equals 14 row a equals 2 row blank rightwards arrow cell 3 a equals 3 cross times 2 end cell row blank equals 6 row blank blank blank end table end style

Jadi nilai dari begin mathsize 14px style 3 a equals 6 end style.

0

Roboguru

Diketahui . Nilai dari  adalah ....

Pembahasan Soal:

Integral atau anti turunan memenuhi algoritma berikut

table attributes columnalign right center left columnspacing 0px end attributes row cell size 14px integral subscript size 14px a superscript size 14px b k x to the power of n size 14px d size 14px x end cell size 14px equals cell right enclose fraction numerator size 14px k size 14px x to the power of size 14px n size 14px minus size 14px 1 end exponent over denominator size 14px n size 14px minus size 14px 1 end fraction end enclose subscript size 14px a superscript size 14px b end cell row blank size 14px equals cell fraction numerator size 14px k size 14px b to the power of size 14px n size 14px minus size 14px 1 end exponent over denominator size 14px n size 14px minus size 14px 1 end fraction size 14px minus fraction numerator size 14px k size 14px a to the power of size 14px n size 14px minus size 14px 1 end exponent over denominator size 14px n size 14px minus size 14px 1 end fraction end cell end table

maka

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell integral subscript a superscript 3 open parentheses 3 x squared plus 2 x plus 1 close parentheses d x end cell equals 25 row cell right enclose 3 over 3 x cubed plus 2 over 2 x squared plus x end enclose subscript a superscript 3 end cell equals 25 row cell open parentheses 3 cubed plus 3 squared plus 3 close parentheses minus open parentheses a cubed plus a squared plus a close parentheses end cell equals 25 row cell 39 minus open parentheses a cubed plus a squared plus a close parentheses end cell equals 25 row cell open parentheses a cubed plus a squared plus a close parentheses end cell equals 14 row a equals 2 row blank rightwards arrow cell 3 a equals 3 cross times 2 end cell row blank equals 6 row blank blank blank end table end style

Jadi nilai dari begin mathsize 14px style 3 a equals 6 end style.

0

Roboguru

Tentukan antiturunan dari

Pembahasan Soal:

begin mathsize 14px style F left parenthesis x right parenthesis equals x to the power of 4 f apostrophe left parenthesis x right parenthesis equals 4 x cubed end style 

Sehingga, antiturunan dari begin mathsize 14px style f apostrophe left parenthesis x right parenthesis equals 4 x cubed end style adalah begin mathsize 14px style F left parenthesis x right parenthesis equals x to the power of 4 plus C end style 

Maka, antiturunan dari begin mathsize 14px style f left parenthesis x right parenthesis equals negative 3 x cubed end style adalah

begin mathsize 14px style f left parenthesis x right parenthesis equals negative 3 x cubed f left parenthesis x right parenthesis equals negative 3 over 4 open parentheses 4 x cubed close parentheses plus C F left parenthesis x right parenthesis equals negative 3 over 4 x to the power of 4 plus C end style 

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Roboguru

Diketahui . Jika maka fungsi  adalah ....

Pembahasan Soal:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell f open parentheses x close parentheses end cell equals cell integral open parentheses 8 x plus 6 close parentheses d x end cell row blank equals cell 4 x squared plus 6 x plus C end cell row blank blank blank row cell f open parentheses negative 2 close parentheses end cell equals 8 row cell 4 open parentheses negative 2 close parentheses squared plus 6 open parentheses negative 2 close parentheses plus C end cell equals 8 row cell 16 minus 12 plus C end cell equals 8 row C equals 4 row blank blank blank row cell f open parentheses x close parentheses end cell equals cell 4 x squared plus 6 x plus 4 end cell end table end style

 

0

Roboguru

Roboguru sudah bisa jawab 91.4% pertanyaan dengan benar

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