Roboguru

Hasil dari  adalah ....

Pertanyaan

Hasil dari open parentheses 3 square root of 3 close parentheses to the power of negative 2 end exponent adalah ....

  1. negative 27 

  2. negative 1 over 27 

  3. 1 over 27 

  4. 27 

Pembahasan Soal:

Gunakan sifat-sifat eksponen berikut.

table attributes columnalign right center left columnspacing 2px end attributes row cell a to the power of negative m end exponent end cell equals cell 1 over a to the power of m comma space a not equal to 0 end cell row cell open parentheses a cross times b close parentheses to the power of m end cell equals cell a to the power of m cross times b to the power of m end cell row cell n-th root of a to the power of m end root end cell equals cell a to the power of m over n end exponent end cell row cell open parentheses a to the power of m close parentheses to the power of n end cell equals cell a to the power of m cross times n end exponent end cell row cell a to the power of 1 end cell equals a end table

Menggunakan sifat-sifat di atas dapat diperoleh:

table attributes columnalign right center left columnspacing 2px end attributes row cell open parentheses 3 square root of 3 close parentheses to the power of negative 2 end exponent end cell equals cell 1 over open parentheses 3 square root of 3 close parentheses squared end cell row blank equals cell fraction numerator 1 over denominator open parentheses 3 close parentheses squared cross times open parentheses square root of 3 close parentheses squared end fraction end cell row blank equals cell fraction numerator 1 over denominator 9 cross times open parentheses 3 to the power of begin display style 1 half end style end exponent close parentheses squared end fraction end cell row blank equals cell fraction numerator 1 over denominator 9 cross times 3 to the power of begin display style 1 half end style cross times 2 end exponent end fraction end cell row blank equals cell fraction numerator 1 over denominator 9 cross times 3 to the power of 1 end fraction end cell row blank equals cell fraction numerator 1 over denominator 9 cross times 3 end fraction end cell row blank equals cell 1 over 27 end cell end table

Jadi, jawaban yang tepat adalah C.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 20 Juli 2021

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