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Hasil dari  adalah ....

Pertanyaan

Hasil dari integral open parentheses 6 x cubed minus 12 x squared plus 3 x minus 7 close parentheses space d x adalah ....

Pembahasan Soal:

Untuk mencari hasil dari integral open parentheses 6 x cubed minus 12 x squared plus 3 x minus 7 close parentheses space d x dengan menggunakan konsep integral tak tentu, rumusnya yaitu :

integral a x to the power of n space d x equals fraction numerator a over denominator n plus 1 end fraction x to the power of n plus 1 end exponent plus straight C comma space untuk space straight n not equal to negative 1

Maka diperoleh,

table attributes columnalign right center left columnspacing 0px end attributes row cell integral open parentheses 6 x cubed minus 12 x squared plus 3 x minus 7 close parentheses space d x end cell equals cell fraction numerator 6 over denominator 3 plus 1 end fraction x to the power of 3 plus 1 end exponent minus fraction numerator 12 over denominator 2 plus 1 end fraction x to the power of 2 plus 1 end exponent plus fraction numerator 3 over denominator 1 plus 1 end fraction x to the power of 1 plus 1 end exponent minus 7 x plus straight C end cell row blank equals cell 6 over 4 straight x to the power of 4 minus 12 over 3 straight x cubed plus 3 over 2 straight x squared minus 7 straight x plus straight C end cell row blank equals cell 3 over 2 straight x to the power of 4 minus 4 straight x cubed plus 3 over 2 straight x squared minus 7 straight x plus straight C end cell end table

Jadi, hasil dari integral open parentheses 6 x cubed minus 12 x squared plus 3 x minus 7 close parentheses space d x adalah Error converting from MathML to accessible text..

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 03 Juni 2021

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