Roboguru
SD
SMP
SMA
UTBK/SNBT

Iklan

Iklan

Pertanyaan

Hasil = ....

Hasil begin mathsize 14px style integral open parentheses sin squared invisible function application space 5 x. cos space invisible function application 5 x close parentheses d x end style = ....

  1. begin mathsize 14px style 1 third sin cubed space 5 x plus C end style

  2. begin mathsize 14px style 1 third cos cubed space 5 x plus C end style

  3. begin mathsize 14px style 1 over 10 sin cubed space 5 x plus C end style

  4. begin mathsize 14px style 1 over 15 cos cubed space 5 x plus C end style

  5. begin mathsize 14px style 1 over 15 sin cubed space 5 x plus C end style

Ke roboguru plus

Iklan

S. Intan

Master Teacher

Mahasiswa/Alumni Institut Pertanian Bogor

Jawaban terverifikasi

Iklan

Pembahasan

begin mathsize 14px style Misalkan straight u equals sin space 5 straight x maka space du equals 5 space cos space 5 straight x space dx rightwards arrow 1 fifth du equals cos space 5 straight x space dx comma space sehingga integral open parentheses sin squared invisible function application space 5 straight x. cos space invisible function application 5 straight x close parentheses dx equals integral straight u squared open parentheses 1 fifth du close parentheses equals 1 fifth open parentheses 1 third straight u cubed close parentheses plus straight C equals 1 fifth open square brackets 1 third sin cubed invisible function application space 5 straight x close square brackets plus straight C equals 1 over 15 sin cubed invisible function application space 5 straight x plus straight C end style

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

23

Iklan

Iklan

Gold Icon

Klaim Gold gratis sekarang!

Dengan Gold kamu bisa tanya soal ke Forum sepuasnya, lho.

Pertanyaan serupa

∫ 4 tan 3 2 ​ x sec 3 2 ​ x d x = …

1

0.0

Jawaban terverifikasi

∫ 4 tan 3 2 ​ x sec 3 2 ​ x d x = …

1

0.0

Jawaban terverifikasi

Iklan

Iklan

Hasil dari ∫ x 2 1 + x 2 ​ 1 ​ d x = ....

3

5.0

Jawaban terverifikasi

Hasil dari ∫ x 2 1 + x 2 ​ 1 ​ d x = ....

3

5.0

Jawaban terverifikasi

Hasil dari ∫ 4 x − x 2 ​ d x adalah...

6

5.0

Jawaban terverifikasi
Ruangguru

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Download di Google Play

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Produk Lainnya

Bantuan & Panduan

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia