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Harga tetapan kesetimbangan untuk reaksi: dip...

Harga tetapan kesetimbangan untuk reaksi:


begin mathsize 14px style Sb subscript 2 S subscript 3 open parentheses italic s close parentheses and 3 H subscript 2 open parentheses italic g close parentheses equilibrium 2 Sb open parentheses italic s close parentheses and 3 H subscript 2 S open parentheses italic g close parentheses end style


diperoleh dari persamaan . . . .space 

  1. begin mathsize 14px style K subscript c equals fraction numerator open square brackets Sb close square brackets squared open square brackets H subscript 2 S close square brackets cubed over denominator open square brackets Sb subscript 2 S subscript 3 close square brackets open square brackets H close square brackets cubed end fraction space end styleundefined 

  2. begin mathsize 14px style K subscript c equals fraction numerator open square brackets Sb subscript 2 S subscript 3 close square brackets open square brackets H subscript 2 close square brackets cubed over denominator open square brackets Sb close square brackets squared open square brackets H subscript 2 S close square brackets cubed end fraction space end styleundefined 

  3. begin mathsize 14px style K subscript c equals open square brackets Sb close square brackets squared open square brackets H subscript 2 S close square brackets cubed end style undefined 

  4. begin mathsize 14px style K subscript c equals open square brackets H subscript 2 S close square brackets cubed over open square brackets H subscript 2 close square brackets cubed space end styleundefined 

  5. begin mathsize 14px style K subscript c equals open square brackets H subscript 2 close square brackets cubed over open square brackets H subscript 2 S close square brackets cubed end styleundefined 

Jawaban:

Hubungan antara komponen dalam kesetimbangan tersebut diungkapkan dalam persamaan tetapan kesetimbangan (begin mathsize 14px style K end style). Oleh karena tetapann kesetimbangan ini didasarkan pada konsentrasi, dilambangkan dengan begin mathsize 14px style K subscript c end style. Untuk kesetimbangan begin mathsize 14px style italic x italic A subscript 2 left parenthesis italic a italic q right parenthesis plus italic y B subscript 2 left parenthesis italic a italic q right parenthesis equilibrium italic z italic A subscript 2 B subscript 2 left parenthesis italic a italic q right parenthesis end style persamaan tetapan kesetimbangannya adalah begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript c space end cell equals cell space fraction numerator left square bracket italic A subscript 2 B subscript 2 right square bracket to the power of italic z over denominator left square bracket italic A subscript 2 right square bracket to the power of italic x open square brackets B subscript 2 close square brackets to the power of italic y end fraction end cell end table end style. Pada kesetimbangan heterogen, tetapan kesetimbangan ditentukan oleh zat berfase gas (begin mathsize 14px style italic g end style) dan larutan (begin mathsize 14px style italic a italic q end style).


Berdasarkan penjelasan di atas, reaksi begin mathsize 14px style Sb subscript 2 S subscript 3 open parentheses italic s close parentheses and 3 H subscript 2 open parentheses italic g close parentheses equilibrium 2 Sb open parentheses italic s close parentheses and 3 H subscript 2 S open parentheses italic g close parentheses end style memiliki nilai begin mathsize 14px style K subscript c space equals space open square brackets H subscript 2 S close square brackets cubed over open square brackets H subscript 2 close square brackets cubed end style.

Jadi, jawaban yang benar adalah D.undefined 

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